How can I escape a double quote inside double quotes?

Question

How can I escape double quotes inside a double string in Bash?

For example, in my shell script

#!/bin/bash

dbload=\"load data local infile \\\"\'gfp         


        

Answer 1

Check out printf...

#!/bin/bash
mystr="say \"hi\""

Without using printf

echo -e $mystr

Output: say "hi"

Using printf

echo -e $(printf '%q' $mystr)

Output: say \"hi\"

Answer 2

I don't know why this old issue popped up today in the Bash tagged listings, but just in case for future researchers, keep in mind that you can avoid escaping by using ASCII codes of the chars you need to echo.

Example:

 echo -e "This is \x22\x27\x22\x27\x22text\x22\x27\x22\x27\x22"
 This is "'"'"text"'"'"

\x22 is the ASCII code (in hex) for double quotes and \x27 for single quotes. Similarly you can echo any character.

I suppose if we try to echo the above string with backslashes, we will need a messy two rows backslashed echo... :)

For variable assignment this is the equivalent:

 $ a=$'This is \x22text\x22'
 $ echo "$a"
 This is "text"

If the variable is already set by another program, you can still apply double/single quotes with sed or similar tools.

Example:

 $ b="Just another text here"
 $ echo "$b"
 Just another text here
 $ sed 's/text/"'\0'"/' <<<"$b" #\0 is a special sed operator
 Just another "0" here #this is not what i wanted to be
 $ sed 's/text/\x22\x27\0\x27\x22/' <<<"$b"
 Just another "'text'" here #now we are talking. You would normally need a dozen of backslashes to achieve the same result in the normal way.

Answer 3

Store the double quote character in a variable:

dqt='"'
echo "Double quotes ${dqt}X${dqt} inside a double quoted string"

Output:

Double quotes "X" inside a double quoted string

Answer 4

Add "\" before double quote to escape it, instead of \

#! /bin/csh -f

set dbtable = balabala

set dbload = "load data local infile "\""'gfpoint.csv'"\"" into table $dbtable FIELDS TERMINATED BY ',' ENCLOSED BY '"\""' LINES TERMINATED BY "\""'\n'"\"" IGNORE 1 LINES"

echo $dbload
# load data local infile "'gfpoint.csv'" into table balabala FIELDS TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY "''" IGNORE 1 LINES

Answer 5

Bash allows you to place strings adjacently, and they'll just end up being glued together.

So this:

$ echo "Hello"', world!'

produces

Hello, world!

The trick is to alternate between single and double-quoted strings as required. Unfortunately, it quickly gets very messy. For example:

$ echo "I like to use" '"double quotes"' "sometimes"

produces

I like to use "double quotes" sometimes

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In your example, I would do it something like this:

$ dbtable=example
$ dbload='load data local infile "'"'gfpoint.csv'"'" into '"table $dbtable FIELDS TERMINATED BY ',' ENCLOSED BY '"'"'"' LINES "'TERMINATED BY "'"'\n'"'" IGNORE 1 LINES'
$ echo $dbload

which produces the following output:

load data local infile "'gfpoint.csv'" into table example FIELDS TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY "'\n'" IGNORE 1 LINES

---

It's difficult to see what's going on here, but I can annotate it using Unicode quotes. The following won't work in bash – it's just for illustration:

dbload=‘load data local infile "’“'gfpoint.csv'”‘" into’“table $dbtable FIELDS TERMINATED BY ',' ENCLOSED BY '”‘"’“' LINES”‘TERMINATED BY "’“'\n'”‘" IGNORE 1 LINES’

The quotes like “ ‘ ’ ” in the above will be interpreted by bash. The quotes like " ' will end up in the resulting variable.

If I give the same treatment to the earlier example, it looks like this:

$ echo“I like to use”‘"double quotes"’“sometimes”

Answer 6

Use a backslash:

echo "\""     # Prints one " character.