I am trying to make this way of finding the last row as I found the last column:
Sheets(\"Sheet2\").Cells(1,Sheets(\"Sheet2\").Columns.Count).End(xlToLeft).C
I use the following function extensively. As pointed out above, using other methods can sometimes give inaccurate results due to used range updates, gaps in the data, or different columns having different row counts.
Example of use:
lastRow=FindRange("Sheet1","A1:A1000")
would return the last occupied row number of the entire range. You can specify any range you want from single columns to random rows, eg FindRange("Sheet1","A100:A150")
Public Function FindRange(inSheet As String, inRange As String) As Long
Set fr = ThisWorkbook.Sheets(inSheet).Range(inRange).find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious)
If Not fr Is Nothing Then FindRange = fr.row Else FindRange = 0
End Function
I use this routine to find the count of data rows. There is a minimum of overhead required, but by counting using a decreasing scale, even a very large result requires few iterations. For example, a result of 28,395 would only require 2 + 8 + 3 + 9 + 5, or 27 times through the loop, instead of a time-expensive 28,395 times.
Even were we to multiply that by 10 (283,950), the iteration count is the same 27 times.
Dim lWorksheetRecordCountScaler as Long
Dim lWorksheetRecordCount as Long
Const sDataColumn = "A" '<----Set to column that has data in all rows (Code, ID, etc.)
'Count the data records
lWorksheetRecordCountScaler = 100000 'Begin by counting in 100,000-record bites
lWorksheetRecordCount = lWorksheetRecordCountScaler
While lWorksheetRecordCountScaler >= 1
While Sheets("Sheet2").Range(sDataColumn & lWorksheetRecordCount + 2).Formula > " "
lWorksheetRecordCount = lWorksheetRecordCount + lWorksheetRecordCountScaler
Wend
'To the beginning of the previous bite, count 1/10th of the scale from there
lWorksheetRecordCount = lWorksheetRecordCount - lWorksheetRecordCountScaler
lWorksheetRecordCountScaler = lWorksheetRecordCountScaler / 10
Wend
lWorksheetRecordCount = lWorksheetRecordCount + 1 'Final answer