NSBezierPath drawing

Question

I want to do a rounded rectangle outline on an NSImage and I figured that using NSBezierPath would be the best way. However, I ran into a problem: instead of drawing a nice

Answer 1

Many rendering systems are derived from the PostScript drawing model. Core Graphics is one of these derivative systems. (Here are some others: PDF, SVG, the HTML Canvas 2D Context, Cairo.)

All of these systems have the idea of stroking a path with a line of some fixed width. When you stroke the path, the line straddles the path: half of the line's width is on one side of the path, and half of the line's width is on the other side. Here's a diagram that may make this clearer:

Now, what happens when you stroke a path that lies along the boundary of your view? Half of the stroke will fall outside of your view's bounds and be clipped away - not drawn. You will only see the half of the stroke that falls inside the view's bounds.

When you use a rounded corner, that corner pulls away from the view's boundary, toward its center, so more of the stroke around the corner falls inside the view's boundary. So the stroke appears to get thicker around the rounded corner, like this:

To fix this, you need to inset your path by half the line width, so that the entire stroke falls inside your view's bounds along the entire path. The default line width is 1.0, so:

NSBezierPath* bp = [NSBezierPath bezierPathWithRoundedRect:
    NSRectInset(self.bounds, 0.5, 0.5) xRadius:5 yRadius:5];

Answer 2

In iOS field, just minus the radius of the circle to prevent from being clipped.

UIBezierPath *roundPath = [UIBezierPath bezierPath];
[roundPath addArcWithCenter:
CGPointMake(self.frame.size.width / 2, self.frame.size.height / 2)
 radius:(self.frame.size.width / 2 - 0.5) 
startAngle:M_PI_2 endAngle:M_PI * 3 / 2.f clockwise:YES];