I have something like
SELECT * FROM table WHERE id IN (118,17,113,23,72);
If I just do this it returns the rows in ID ascending order. Is t
You can create a temp table with two columns (ID, order_num):
ID order_num
118 1
17 2
113 3
23 4
72 5
Then join:
SELECT * from table
INNER JOIN #temp_table
ON table.id = #temp_table.id
Notice that you can drop the IN
clause.
Sometimes I actually create a permanent table, because then when the client inevitably changes their mind about the ordering, I don't have to touch the code, just the table.
Edit
The answer using ORDER BY FIELD() (which I didn't know about) is probably what you want.
this is the first thing that pops to mind. note sql is untested, you might need to check correct syntax
its a bit cumbersome, but might do the trick
select * from table where id = 118
union
select * from table where id = 17
union
.... and so on
I think if you did a UNION
query with each select, it might return it in the order.
SELECT * FROM table WHERE id=118
UNION
SELECT * FROM table WHERE id=17
...
Ugly, but I think it will work.
You should use "ORDER BY FIELD". So, for instance:
SELECT * FROM table WHERE id IN (118,17,113,23,72)
ORDER BY FIELD(id,118,17,113,23,72)
You can create a number to sort on based on the id values:
select *
from table
where id in (118,17,113,23,72)
order by
case id
when 118 then 1
when 17 then 2
when 133 then 3
when 23 then 4
when 72 then 5
end
Try using FIND_IN_SET:
SELECT * FROM table WHERE id IN (118,17,113,23,72)
ORDER BY FIND_IN_SET(id, '118,17,113,23,72');