Bash script to run php script

Question

I have a php script that I want to be run using a bash script, so I can use Cron to run the php script every minute or so.

As far as I\'m aware I need to create the

Answer 1

I found php-cgi on my server. And its on environment path so I was able to run from anywhere. I executed succesfuly file.php in my bash script.

#!/bin/bash
php-cgi ../path/file.php

And the script returned this after php script was executed:

X-Powered-By: PHP/7.1.1 Content-type: text/html; charset=UTF-8

done!

By the way, check first if it works by checking the version issuing the command php-cgi -v

Answer 2

I'm pretty sure something like this is what you are looking for:

#!/bin/sh

php /pathToScript/script.php

Save that with your desired script name (such as runPHP.sh) and give it execution rights, then you can use it however you want.

Edit: You might as well not use a bash script at all and just add the "php ..." command to the crontab, if I'm not mistaken.

Good luck!

Answer 3

If you have PHP installed as a command line tool (try issuing php to the terminal and see if it works), your shebang (#!) line needs to look like this:

#!/usr/bin/php

Put that at the top of your script, make it executable (chmod +x myscript.php), and make a Cron job to execute that script (same way you'd execute a bash script).

You can also use php myscript.php.

Answer 4

You just need to set :

/usr/bin/php path_to_your_php_file

in your crontab.

Answer 5

The bash script should be something like this:

#!/bin/bash
/usr/bin/php /path/to/php/file.php

You need the php executable (usually found in /usr/bin) and the path of the php script to be ran. Now you only have to put this bash script on crontab and you're done!

Answer 6

a quick way to find out WHERE YOUR particular executable is located on your $PATH, try.

Even quicker way to find out where php is ...

whereis php

I'm running debian and above command showing me

php: /usr/bin/php /usr/share/php /usr/share/man/man1/php.1.gz

Hope that helps.