Regular Expression: Any character that is NOT a letter or number

Question

I\'m trying to figure out the regular expression that will match any character that is not a letter or a number. So characters such as (,,@,£,() etc ...

Once found I

Answer 1

To match anything other than letter or number you could try this:

[^a-zA-Z0-9]

And to replace:

var str = 'dfj,dsf7lfsd .sdklfj';
str = str.replace(/[^A-Za-z0-9]/g, ' ');

Answer 2

You are looking for:

var yourVar = '1324567890abc§$)%';
yourVar = yourVar.replace(/[^a-zA-Z0-9]/g, ' ');

This replaces all non-alphanumeric characters with a space.

The "g" on the end replaces all occurrences.

Instead of specifying a-z (lowercase) and A-Z (uppercase) you can also use the in-case-sensitive option: /[^a-z0-9]/gi.

Answer 3

• Match letters only /[A-Z]/ig
• Match anything not letters /[^A-Z]/ig
• Match number only /[0-9]/g or /\d+/g
• Match anything not number /[^0-9]/g or /\D+/g
• Match anything not number or letter /[^A-Z0-9]/ig

There are other possible patterns

Answer 4

try doing str.replace(/[^\w]/); It will replace all the non-alphabets and numbers from your string!

Edit 1: str.replace(/[^\w]/g, ' ')

Answer 5

This regular expression matches anything that isn't a letter, digit, or an underscore (_) character.

\W

For example in JavaScript:

"(,,@,£,() asdf 345345".replace(/\W/g, ' '); // Output: "          asdf 345345"

Answer 6

Have you tried str = str.replace(/\W|_/g,''); it will return a string without any character and you can specify if any especial character after the pipe bar | to catch them as well.

var str = "1324567890abc§$)% John Doe #$@'.replace(/\W|_/g, ''); it will return str = 1324567890abcJohnDoe

or look for digits and letters and replace them for empty string (""):

var str = "1324567890abc§$)% John Doe #$@".replace(/\w|_/g, ''); it will return str = '§$)% #$@';