RegEx for Javascript to allow only alphanumeric

Question

I need to find a reg ex that only allows alphanumeric. So far, everyone I try only works if the string is alphanumeric, meaning contains both a letter and a number. I just w

Answer 1

/^[a-z0-9]+$/i

^         Start of string
[a-z0-9]  a or b or c or ... z or 0 or 1 or ... 9
+         one or more times (change to * to allow empty string)
$         end of string    
/i        case-insensitive

Update (supporting universal characters)

if you need to this regexp supports universal character you can find list of unicode characters here.

for example: /^([a-zA-Z0-9\u0600-\u06FF\u0660-\u0669\u06F0-\u06F9 _.-]+)$/

this will support persian.

Answer 2

Input these code to your SCRATCHPAD and see the action.

var str=String("Blah-Blah1_2,oo0.01&zz%kick").replace(/[^\w-]/ig, '');

Answer 3

Even better than Gayan Dissanayake pointed out.

/^[-\w\s]+$/

Now ^[a-zA-Z0-9]+$ can be represented as ^\w+$

You may want to use \s instead of space. Note that \s takes care of whitespace and not only one space character.

Answer 4

I have string similar to Samsung Galaxy A10s 6.2-Inch (2GB,32GB ROM) Android 9.0, (13MP+2MP)+ 8MP Dual SIM 4000mAh 4G LTE Smartphone - Black (BF19)

Below is what i did:

string.replace(/[^a-zA-Z0-9 ,._-]/g, '').split(',').join('-').split(' ').join('-').toLowerCase()

Notice i allowed ,._- then use split() and join() to replace , to - and space to - respectively.

I ended up getting something like this: samsung-galaxy-a10s-6.2-inch-2gb-32gb-rom-android-9.0-13mp-2mp-8mp-dual-sim-4000mah-4g-lte-smartphone-black-bf19-20 which is what i wanted.

There might be a better solution but this is what i found working fine for me.

Answer 5

Save this constant

const letters = /^[a-zA-Z0-9]+$/

now, for checking part use .match()

const string = 'Hey there...' // get string from a keyup listner
let id = ''
// iterate through each letters
for (var i = 0; i < string.length; i++) {
  if (string[i].match(letters) ) {
    id += string[i]
  } else {
    // In case you want to replace with something else
    id += '-'  
  }
}
return id

Answer 6

This will work

^(?=.*[a-zA-Z])(?=.*[0-9])[a-zA-Z0-9]+$

It accept only alphanumeriuc characters alone:
test cases pased :

dGgs1s23 - valid
12fUgdf  - valid,
121232   - invalid, 
abchfe   - invalid,
 abd()*  - invalid, 
42232^5$ - invalid

or

You can also try this one. this expression satisfied at least one number and one character and no other special characters

^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$

in angular can test like:

$scope.str = '12fUgdf';
var pattern = new RegExp('^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$');
$scope.testResult = pattern.test($scope.str);

PLUNKER DEMO

Refered:Regular expression for alphanumeric in Angularjs