The concurrent.futures.Executor.map takes a variable number of iterables from which the function given is called. How should I call it if I have a generator that pro
You need to remove the *
on the map
call:
args = ((a, b) for b in c)
for result in executor.map(f, args):
pass
This will call f
, len(args)
times, where f
should accept one parameter.
If you want f
to accept two parameters you can use a lambda call like:
args = ((a, b) for b in c)
for result in executor.map(lambda p: f(*p), args): # (*p) does the unpacking part
pass
I have seen so many answers here, but none of them is as straight forward as using lambda expressions:
foo(x,y): pass
want to call above method 10 times, with same value i.e. xVal and yVal? with concurrent.futures.ThreadPoolExecutor() as executor:
for _ in executor.map( lambda _: foo(xVal, yVal), range(0, 10)):
pass
For ProcessPoolExecutor.map():
Similar to map(func, *iterables) except:
the iterables are collected immediately rather than lazily;
func is executed asynchronously and several calls to func may be made concurrently.
Try running the following snippet under python 3, and you will be quite clear:
from concurrent.futures import ProcessPoolExecutor
def f(a, b):
print(a+b)
with ProcessPoolExecutor() as pool:
pool.map(f, (0, 1, 2, 3, 4, 5, 6, 7, 8, 9), (0, 1, 2))
# 0, 2, 4
array = [(i, i) for i in range(3)]
with ProcessPoolExecutor() as pool:
pool.map(f, *zip(*array))
# 0, 2, 4
So suppose you have a function with takes 3 arguments and all the 3 arguments are dynamic and keep on changing with every call. For example:
def multiply(a,b,c):
print(a * b * c)
To call this multiple times using threading, I would first create a list of tuples where each tuple is a version of a,b,c:
arguments = [(1,2,3), (4,5,6), (7,8,9), ....]
To we know that concurrent.futures
's map
function would accept first argument as the target function and second argument as the list of arguments for each version of the function that will be execute. Therefore, you might make a call like this:
for _ in executor.map(multiply, arguments) # Error
But this will give you error that the function expected 3 arguments but got only 1
. To solve this problem, we create a helper function:
def helper(numbers):
multiply(numbers[0], numbers[1], numbers[2])
Now, we can call this function using executor as follow:
with ThreadPoolExecutor() as executor:
for _ in executor.map(helper, arguments):
pass
That should give you the desired results.
c
from itertools import repeat
for result in executor.map(f, repeat(a), c):
pass
c
, and can unpack c
from itertools import izip
for result in executor.map(f, *izip(*c)):
pass
c
, can't unpack c
f
to take a single argument and unpack the argument in the function.If each item in c
has a variable number of members, or you're calling f
only a few times:
executor.map(lambda args, f=f: f(*args), c)
It defines a new function that unpacks each item from c
and calls f
. Using a default argument for f
in the lambda
makes f
local inside the lambda
and so reduces lookup time.
If you've got a fixed number of arguments, and you need to call f
a lot of times:
from collections import deque
def itemtee(iterable, n=2):
def gen(it = iter(iterable), items = deque(), next = next):
popleft = items.popleft
extend = items.extend
while True:
if not items:
extend(next(it))
yield popleft()
return [gen()] * n
executor.map(f, *itemtee(c, n))
Where n
is the number of arguments to f
. This is adapted from itertools.tee.
You can use currying to create new function via partial method in Python
from concurrent.futures import ThreadPoolExecutor
from functools import partial
def some_func(param1, param2):
# some code
# currying some_func with 'a' argument is repeated
func = partial(some_func, a)
with ThreadPoolExecutor() as executor:
executor.map(func, list_of_args):
...
If you need to pass more than one the same parameters you can pass them to partial method
func = partial(some_func, a, b, c)