How can I delete all Git branches which have been merged?

Question

I have many Git branches. How do I delete branches which have already been merged? Is there an easy way to delete them all instead of deleting them one by one?

Answer 1

If you're on Windows you can use Windows Powershell or Powershell 7 with Out-GridView to have a nice list of branches and select with mouse which one you want to delete:

git branch --format "%(refname:short)" --merged  | Out-GridView -PassThru | % { git branch -d $_ }

after clicking OK Powershell will pass this branches names to git branch -d command and delete them

Answer 2

Just extending Adam's answer a little bit:

Add this to your Git configuration by running git config -e --global

[alias]
    cleanup = "!git branch --merged | grep  -v '\\*\\|master\\|develop' | xargs -n 1 git branch -d"

And then you can delete all the local merged branches doing a simple git cleanup.

Answer 3

This also works to delete all merged branches except master.

git branch --merged | grep -v '^* master$' | grep -v '^  master$' | xargs git branch -d

Answer 4

I've been using the following method to remove merged local AND remote branches in one cmd.

I have the following in my bashrc file:

function rmb {
  current_branch=$(git branch --no-color 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/\1/')
  if [ "$current_branch" != "master" ]; then
    echo "WARNING: You are on branch $current_branch, NOT master."
  fi
  echo "Fetching merged branches..."
  git remote prune origin
  remote_branches=$(git branch -r --merged | grep -v '/master$' | grep -v "/$current_branch$")
  local_branches=$(git branch --merged | grep -v 'master$' | grep -v "$current_branch$")
  if [ -z "$remote_branches" ] && [ -z "$local_branches" ]; then
    echo "No existing branches have been merged into $current_branch."
  else
    echo "This will remove the following branches:"
    if [ -n "$remote_branches" ]; then
      echo "$remote_branches"
    fi
    if [ -n "$local_branches" ]; then
      echo "$local_branches"
    fi
    read -p "Continue? (y/n): " -n 1 choice
    echo
    if [ "$choice" == "y" ] || [ "$choice" == "Y" ]; then
      # Remove remote branches
      git push origin `git branch -r --merged | grep -v '/master$' | grep -v "/$current_branch$" | sed 's/origin\//:/g' | tr -d '\n'`
      # Remove local branches
      git branch -d `git branch --merged | grep -v 'master$' | grep -v "$current_branch$" | sed 's/origin\///g' | tr -d '\n'`
    else
      echo "No branches removed."
    fi
  fi
}

original source

This doesn't delete the master branch, but removes merged local AND remote branches. Once you have this in you rc file, just run rmb, you're shown a list of merged branches that will be cleaned and asked for confirmation on the action. You can modify the code to not ask for confirmation as well, but it's probably good to keep it in.

Answer 5

I've used Adam's answer for years now. That said, that there are some cases where it wasn't behaving as I expected:

1. branches that contained the word "master" were ignored, e.g. "notmaster" or "masterful", rather than only the master branch
2. branches that contained the word "dev" were ignored, e.g. "dev-test", rather than only the dev branch
3. deleting branches that are reachable from the HEAD of the current branch (that is, not necessarily master)
4. in detached HEAD state, deleting every branch reachable from the current commit

1 & 2 were straightforward to address, with just a change to the regex. 3 depends on the context of what you want (i.e. only delete branches that haven't been merged into master or against your current branch). 4 has the potential to be disastrous (although recoverable with git reflog), if you unintentionally ran this in detached HEAD state.

Finally, I wanted this to all be in a one-liner that didn't require a separate (Bash|Ruby|Python) script.

TL;DR

Create a git alias "sweep" that accepts an optional -f flag:

git config --global alias.sweep '!git branch --merged $([[ $1 != "-f" ]] \
&& git rev-parse master) | egrep -v "(^\*|^\s*(master|develop)$)" \
| xargs git branch -d'

and invoke it with:

git sweep

or:

git sweep -f

The long, detailed answer

It was easiest for me to create an example git repo with some branches and commits to test the correct behavior:

Create a new git repo with a single commit

mkdir sweep-test && cd sweep-test && git init
echo "hello" > hello
git add . && git commit -am "initial commit"

Create some new branches

git branch foo && git branch bar && git branch develop && git branch notmaster && git branch masterful
git branch --list

  bar
  develop
  foo
* master
  masterful
  notmaster

Desired behavior: select all merged branches except: master, develop or current

The original regex misses the branches "masterful" and "notmaster" :

git checkout foo
git branch --merged | egrep -v "(^\*|master|dev)"

  bar

With the updated regex (which now excludes "develop" rather than "dev"):

git branch --merged | egrep -v "(^\*|^\s*(master|develop)$)"

bar
masterful
notmaster

Switch to branch foo, make a new commit, then checkout a new branch, foobar, based on foo:

echo "foo" > foo
git add . && git commit -am "foo"
git checkout -b foobar
echo "foobar" > foobar
git add . && git commit -am "foobar"

My current branch is foobar, and if I re-run the above command to list the branches I want to delete, the branch "foo" is included even though it hasn't been merged into master:

git branch --merged | egrep -v "(^\*|^\s*(master|develop)$)"

  bar
  foo
  masterful
  notmaster

However, if I run the same command on master, the branch "foo" is not included:

git checkout master && git branch --merged | egrep -v "(^\*|^\s*(master|develop)$)"

  bar
  masterful
  notmaster

And this is simply because git branch --merged defaults to the HEAD of the current branch if not otherwise specified. At least for my workflow, I don't want to delete local branches unless they've been merged to master, so I prefer the following variant:

git checkout foobar
git branch --merged $(git rev-parse master) | egrep -v "(^\*|^\s*(master|develop)$)"

  bar
  masterful
  notmaster

Detached HEAD state

Relying on the default behavior of git branch --merged has even more significant consequences in detached HEAD state:

git checkout foobar
git checkout HEAD~0
git branch --merged | egrep -v "(^\*|^\s*(master|develop)$)"

  bar
  foo
  foobar
  masterful
  notmaster

This would have deleted the branch I was just on, "foobar" along with "foo", which is almost certainly not the desired outcome. With our revised command, however:

git branch --merged $(git rev-parse master) | egrep -v "(^\*|^\s*(master|develop)$)"

  bar
  masterful
  notmaster

One line, including the actual delete

git branch --merged $(git rev-parse master) | egrep -v "(^\*|^\s*(master|develop)$)" | xargs git branch -d

All wrapped up into a git alias "sweep":

git config --global alias.sweep '!git branch --merged $([[ $1 != "-f" ]] \
&& git rev-parse master) | egrep -v "(^\*|^\s*(master|develop)$)" \
| xargs git branch -d'

The alias accepts an optional -f flag. The default behavior is to only delete branches that have been merged into master, but the -f flag will delete branches that have been merged into the current branch.

git sweep

Deleted branch bar (was 9a56952).
Deleted branch masterful (was 9a56952).
Deleted branch notmaster (was 9a56952).

git sweep -f

Deleted branch foo (was 2cea1ab).

Answer 6

Git Sweep does a great job of this.