Why equal to operator does not work if it is not surrounded by space?

Question

I tried the following script

#!/bin/bash
var1=\"Test 1\" 
var2=\"Test 2\"
if [ \"$var1\"=\"$var2\" ] 
  then 
    echo \"Equal\" 
  else 
    echo \"Not equa         


        

Answer 1

To add to the existing explanation, "$var1"="$var2" is just a single non-empty string, and thus always evaluates as true in a conditional.

[ "$var1"="$var2" ] && echo true

The above command will always print out true (even if var1 and var2 be empty).

Answer 2

test (or [ expr ]) is a builtin function. Like all functions in bash, you pass it's arguments as whitespace separated words.

As the man page for bash builtins states: "Each operator and operand must be a separate argument."

It's just the way bash and most other Unix shells work.

Variable assignment is different.

In bash a variable assignment has the syntax: name=[value]. You cannot put unquoted spaces around the = because bash would not interpret this as the assignment you intend. bash treats most lists of words as a command with parameters.

E.g.

# call the command or function 'abc' with '=def' as argument
abc =def

# call 'def' with the variable 'abc' set to the empty string
abc= def

# call 'ghi' with 'abc' set to 'def'
abc=def ghi

# set 'abc' to 'def ghi'
abc="def ghi"

Answer 3

In bash the best is to use [[ ]]:

x="test"
y="test"
if [[ "${x}" = "${y}" ]]; then
    echo "Equals"
else
    echo "No equals"
fi

Answer 4

When the shell reads

if [ "$var1" = "$var2" ]

it invokes the command [ with 4 arguments. Whether [ is a builtin or an external command is irrelevant, but it may help to understand that it may be the external command /bin/[. The second argument is the literal '=' and the fourth is ']'. However, when the shell reads

if [ "$var1"= "$var2" ]

[ only gets 3 arguments: the expansion of $var1 with '=' appended, the expansion of $var2, and ']'. When it gets only 3 arguments, it expects the last argument to be ']' and the first argument to be a unary operator.