Convert JSON String To C# Object

Question

Trying to convert a JSON string into an object in C#. Using a really simple test case:

JavaScriptSerializer json_serializer = new JavaScriptSerializer();
obj         


        

Answer 1

add this ddl to reference to your project: System.Web.Extensions.dll

use this namespace: using System.Web.Script.Serialization;

public class IdName
{
    public int Id { get; set; }
    public string Name { get; set; }
}


   string jsonStringSingle = "{'Id': 1, 'Name':'Thulasi Ram.S'}".Replace("'", "\"");
   var entity = new JavaScriptSerializer().Deserialize<IdName>(jsonStringSingle);

   string jsonStringCollection = "[{'Id': 2, 'Name':'Thulasi Ram.S'},{'Id': 2, 'Name':'Raja Ram.S'},{'Id': 3, 'Name':'Ram.S'}]".Replace("'", "\"");
   var collection = new JavaScriptSerializer().Deserialize<IEnumerable<IdName>>(jsonStringCollection);

Answer 2

You can accomplished your requirement easily by using Newtonsoft.Json library. I am writing down the one example below have a look into it.

Class for the type of object you receive:

public class User
{
    public int ID { get; set; }
    public string Name { get; set; }

}

Code:

static void Main(string[] args)
{

      string json = "{\"ID\": 1, \"Name\": \"Abdullah\"}";

      User user = JsonConvert.DeserializeObject<User>(json);

      Console.ReadKey();
}

this is a very simple way to parse your json.

Answer 3

Another fast and easy way to semi-automate these steps is to:

1. take the JSON you want to parse and paste it here: https://app.quicktype.io/ . Change language to C# in the drop down.
2. Update the name in the top left to your class name, it defaults to "Welcome".
3. In visual studio go to Website -> Manage Packages and use NuGet to add Json.Net from Newtonsoft.

4. app.quicktype.io generated serialize methods based on Newtonsoft. Alternatively, you can now use code like:

   WebClient client = new WebClient();

   string myJSON = client.DownloadString("https://URL_FOR_JSON.com/JSON_STUFF");

   var myClass = Newtonsoft.Json.JsonConvert.DeserializeObject(myJSON);

Answer 4

You probably don't want to just declare routes_list as an object type. It doesn't have a .test property, so you really aren't going to get a nice object back. This is one of those places where you would be better off defining a class or a struct, or make use of the dynamic keyword.

If you really want this code to work as you have it, you'll need to know that the object returned by DeserializeObject is a generic dictionary of string,object. Here's the code to do it that way:

var json_serializer = new JavaScriptSerializer();
var routes_list = (IDictionary<string, object>)json_serializer.DeserializeObject("{ \"test\":\"some data\" }");
Console.WriteLine(routes_list["test"]);

If you want to use the dynamic keyword, you can read how here.

If you declare a class or struct, you can call Deserialize instead of DeserializeObject like so:

class MyProgram {
    struct MyObj {
        public string test { get; set; }
    }

    static void Main(string[] args) {
        var json_serializer = new JavaScriptSerializer();
        MyObj routes_list = json_serializer.Deserialize<MyObj>("{ \"test\":\"some data\" }");
        Console.WriteLine(routes_list.test);

        Console.WriteLine("Done...");
        Console.ReadKey(true);
    }
}

Answer 5

Copy your Json and paste at textbox on json2csharp and click on Generate button.

A cs class will be generated use that cs file as below

var generatedcsResponce = JsonConvert.DeserializeObject(yourJson);

Where RootObject is the name of the generated cs file;

Answer 6

Or, you can use the Newtownsoft.Json library as follows:

using Newtonsoft.Json;
...
var result = JsonConvert.DeserializeObject<T>(json);

Where T is your object type that matches your JSON string.