Changing user agent on urllib2.urlopen

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感动是毒
感动是毒 2020-11-22 13:59

How can I download a webpage with a user agent other than the default one on urllib2.urlopen?

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  • 2020-11-22 14:46

    there are two properties of urllib.URLopener() namely:
    addheaders = [('User-Agent', 'Python-urllib/1.17'), ('Accept', '*/*')] and
    version = 'Python-urllib/1.17'.
    To fool the website you need to changes both of these values to an accepted User-Agent. for e.g.
    Chrome browser : 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/33.0.1750.149 Safari/537.36'
    Google bot : 'Googlebot/2.1'
    like this

    import urllib
    page_extractor=urllib.URLopener()  
    page_extractor.addheaders = [('User-Agent', 'Googlebot/2.1'), ('Accept', '*/*')]  
    page_extractor.version = 'Googlebot/2.1'
    page_extractor.retrieve(<url>, <file_path>)
    

    changing just one property does not work because the website marks it as a suspicious request.

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  • 2020-11-22 14:48

    I answered a similar question a couple weeks ago.

    There is example code in that question, but basically you can do something like this: (Note the capitalization of User-Agent as of RFC 2616, section 14.43.)

    opener = urllib2.build_opener()
    opener.addheaders = [('User-Agent', 'Mozilla/5.0')]
    response = opener.open('http://www.stackoverflow.com')
    
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  • 2020-11-22 14:51

    Setting the User-Agent from everyone's favorite Dive Into Python.

    The short story: You can use Request.add_header to do this.

    You can also pass the headers as a dictionary when creating the Request itself, as the docs note:

    headers should be a dictionary, and will be treated as if add_header() was called with each key and value as arguments. This is often used to “spoof” the User-Agent header, which is used by a browser to identify itself – some HTTP servers only allow requests coming from common browsers as opposed to scripts. For example, Mozilla Firefox may identify itself as "Mozilla/5.0 (X11; U; Linux i686) Gecko/20071127 Firefox/2.0.0.11", while urllib2‘s default user agent string is "Python-urllib/2.6" (on Python 2.6).

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  • 2020-11-22 14:54

    Another solution in urllib2 and Python 2.7:

    req = urllib2.Request('http://www.example.com/')
    req.add_unredirected_header('User-Agent', 'Custom User-Agent')
    urllib2.urlopen(req)
    
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  • 2020-11-22 14:55

    Try this :

    html_source_code = requests.get("http://www.example.com/",
                       headers={'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.107 Safari/537.36',
                                'Upgrade-Insecure-Requests': '1',
                                'x-runtime': '148ms'}, 
                       allow_redirects=True).content
    
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  • 2020-11-22 14:59

    All these should work in theory, but (with Python 2.7.2 on Windows at least) any time you send a custom User-agent header, urllib2 doesn't send that header. If you don't try to send a User-agent header, it sends the default Python / urllib2

    None of these methods seem to work for adding User-agent but they work for other headers:

    opener = urllib2.build_opener(proxy)
    opener.addheaders = {'User-agent':'Custom user agent'}
    urllib2.install_opener(opener)
    
    request = urllib2.Request(url, headers={'User-agent':'Custom user agent'})
    
    request.headers['User-agent'] = 'Custom user agent'
    
    request.add_header('User-agent', 'Custom user agent')
    
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