Laravel Eloquent: Ordering results of all()

Question

I\'m stuck on a simple task. I just need to order results coming from this call

$results = Project::all();

Where Project is

Answer 1

DO THIS:

$results = Project::orderBy('name')->get();

Why? Because it's fast! The ordering is done in the database.

DON'T DO THIS:

$results = Project::all()->sortBy('name');

Why? Because it's slow. First, the the rows are loaded from the database, then loaded into Laravel's Collection class, and finally, ordered in memory.

Answer 2

While you need result for date as desc

$results = Project::latest('created_at')->get();

Answer 3

You instruction require call to get, because is it bring the records and orderBy the catalog

$results = Project::orderBy('name')
           ->get();

Example:

$results = Result::where ('id', '>=', '20')
->orderBy('id', 'desc')
->get();

In the example the data is filtered by "where" and bring records greater than 20 and orderBy catalog by order from high to low.

Answer 4

You can actually do this within the query.

$results = Project::orderBy('name')->get();

This will return all results with the proper order.

Answer 5

Note, you can do:

$results = Project::select('name')->orderBy('name')->get();

This generate a query like:

"SELECT name FROM proyect ORDER BY 'name' ASC"

In some apps when the DB is not optimized and the query is more complex, and you need prevent generate a ORDER BY in the finish SQL, you can do:

$result = Project::select('name')->get();
$result = $result->sortBy('name');
$result = $result->values()->all();

Now is php who order the result.

Answer 6

You could still use sortBy (at the collection level) instead of orderBy (at the query level) if you still want to use all() since it returns a collection of objects.

Ascending Order

$results = Project::all()->sortBy("name");

Descending Order

$results = Project::all()->sortByDesc("name");

Check out the documentation about Collections for more details.

https://laravel.com/docs/5.1/collections