How do I make an html link look like a button?

Question

I\'m using ASP.NET, some of my buttons just do redirects. I\'d rather they were ordinary links, but I don\'t want my users to notice much difference in the appearance. I c

Answer 1

This gets into the details of the css a bit more too, and gives you some images:

http://www.dynamicdrive.com/style/csslibrary/item/css_square_buttons/

Answer 2

Simple button css now you can play around with your editor

a {
  display: inline-block;
  background: #000000c9;
  color: #000;
  padding: 12px 24px;
  text-align: center;
  text-decoration: none;
  font-size: 16px;
  cursor: pointer;
}
a:hover {
  background:#000
  cursor: pointer;
  transition: 0.3s ease-in;
}

Link tag

<a href="#">Hover me<a>

Answer 3

Apply this class to it

.button {
  font: bold 11px Arial;
  text-decoration: none;
  background-color: #EEEEEE;
  color: #333333;
  padding: 2px 6px 2px 6px;
  border-top: 1px solid #CCCCCC;
  border-right: 1px solid #333333;
  border-bottom: 1px solid #333333;
  border-left: 1px solid #CCCCCC;
}

<a href="#" class="button">Example</a>

Answer 4

Why not just wrap an anchor tag around a button element.

<a href="somepage.html"><button type="button">Text of Some Page</button></a>

This will work for IE9+, Chrome, Safari, Firefox, and probably Opera.

Answer 5

Much belated answer:

I've been wrestling with this on and off since I first started working in ASP. Here's the best I've come up with:

Concept: I create a custom control that has a tag. Then in the button I put an onclick event that sets document.location to the desired value with JavaScript.

I called the control ButtonLink, so that I could easily get if confused with LinkButton.

aspx:

<%@ Control Language="VB" AutoEventWireup="false" CodeFile="ButtonLink.ascx.vb" Inherits="controls_ButtonLink" %>

<asp:Button runat="server" ID="button"/>

code behind:

Partial Class controls_ButtonLink
Inherits System.Web.UI.UserControl

Dim _url As String
Dim _confirm As String

Public Property NavigateUrl As String
    Get
        Return _url
    End Get
    Set(value As String)
        _url = value
        BuildJs()
    End Set
End Property
Public Property confirm As String
    Get
        Return _confirm
    End Get
    Set(value As String)
        _confirm = value
        BuildJs()
    End Set
End Property
Public Property Text As String
    Get
        Return button.Text
    End Get
    Set(value As String)
        button.Text = value
    End Set
End Property
Public Property enabled As Boolean
    Get
        Return button.Enabled
    End Get
    Set(value As Boolean)
        button.Enabled = value
    End Set
End Property
Public Property CssClass As String
    Get
        Return button.CssClass
    End Get
    Set(value As String)
        button.CssClass = value
    End Set
End Property

Sub BuildJs()
    ' This is a little kludgey in that if the user gives a url and a confirm message, we'll build the onclick string twice.
    ' But it's not that big a deal.
    If String.IsNullOrEmpty(_url) Then
        button.OnClientClick = Nothing
    ElseIf String.IsNullOrEmpty(_confirm) Then
        button.OnClientClick = String.Format("document.location='{0}';return false;", ResolveClientUrl(_url))
    Else
        button.OnClientClick = String.Format("if (confirm('{0}')) {{document.location='{1}';}} return false;", _confirm, ResolveClientUrl(_url))
    End If
End Sub
End Class

Advantages of this scheme: It looks like a control. You write a single tag for it, <ButtonLink id="mybutton" navigateurl="blahblah"/>

The resulting button is a "real" HTML button and so looks just like a real button. You don't have to try to simulate the look of a button with CSS and then struggle with different looks on different browsers.

While the abilities are limited, you can easily extend it by adding more properties. It's likely that most properties would just have to "pass thru" to the underlying button, like I did for text, enabled and cssclass.

If anybody's got a simpler, cleaner or otherwise better solution, I'd be happy to hear it. This is a pain, but it works.

Answer 6

Use below snippet.

    .a{
  color: $brn-acc-clr;
  background-color: transparent;
  border-color: #888888;

  &:hover:active{
    outline: none;
    color: #888888;
    border-color: #888888;
  }
  &:fill{
    background-color: #888888;
    color: #fff;
    box-shadow: 0 3px 10px rgba(#888888, 0.5);
    &:hover:active{
      color: #fff;
    }
    &:hover:not(:disabled){
      transform: translateY(-2px);
      background-color: darken(#888888, 4);
    }
  }
}