#include
int main(void)
{
int i=10;
if(i==(20||10))
printf(\"True\");
else
printf(\"False\");
return 0;
}
look at if(i==(20||10))
. Due to the inner parentheses, 20||10
is evaluated first, yielding 1
. Then, variable i
, whose value is 10
is compared to 1
, resulting 0
.
In C, and 0
stands for False
, while all non-zero values means True
. So the condition comes to be False
. Thus, "False" is printed.
This line if(i==(20||10))
always evaluates to i==1
as Alk
said in comments - (20||10)
evaluates to 1
, hence when you compare i == 1
, that is why you get False
as the output. A non-Zero value in C
implies true.
Read about Short-circuit evaluation
Perhaps this is what you wanted:
int i=10;
if(i==20 || i == 10)
printf("True");
else
printf("False");