JQuery .each() backwards

Question

I\'m using JQuery to select some elements on a page and then move them around in the DOM. The problem I\'m having is I need to select all the elements in the reverse order t

Answer 1

You cannot iterate backwards with the jQuery each function, but you can still leverage jQuery syntax.

Try the following:

//get an array of the matching DOM elements   
var liItems = $("ul#myUL li").get();

//iterate through this array in reverse order    
for(var i = liItems.length - 1; i >= 0; --i)
{
  //do Something
}

Answer 2

I found Array.prototype.reverse unsuccessful with objects, so I made a new jQuery function to use as an alternative: jQuery.eachBack(). It iterates through as the normal jQuery.each() would, and stores each key into an array. It then reverses that array and performs the callback on the original array/object in the order of the reversed keys.

jQuery.eachBack=function (obj, callback) {
    var revKeys=[]; $.each(obj,function(rind,rval){revKeys.push(rind);}); 
    revKeys.reverse();
    $.each(revKeys,function (kind,i){
        if(callback.call(obj[i], i, obj[i]) === false) {    return false;}
    });
    return obj;
}   
jQuery.fn.eachBack=function (callback,args) {
    return jQuery.eachBack(this, callback, args);
}

Answer 3

Needed to do a reverse on $.each so i used Vinay idea:

//jQuery.each(collection, callback) =>
$.each($(collection).get().reverse(), callback func() {});

worked nicely, thanks

Answer 4

You can also try

var arr = [].reverse.call($('li'))
arr.each(function(){ ... })

Answer 5

I think u need

.parentsUntill()

Answer 6

If you don't want to save method into jQuery.fn you can use

[].reverse.call($('li'));