How to get multiple counts with one SQL query?

Question

I am wondering how to write this query.

I know this actual syntax is bogus, but it will help you understand what I am wanting. I need it in this format, because it i

Answer 1

Based on Bluefeet's accepted response with an added nuance using OVER():

SELECT distributor_id,
    COUNT(*) total,
    SUM(case when level = 'exec' then 1 else 0 end) OVER() ExecCount,
    SUM(case when level = 'personal' then 1 else 0 end) OVER () PersonalCount
FROM yourtable
GROUP BY distributor_id

Using OVER() with nothing in the () will give you the total count for the whole dataset.

Answer 2

SELECT 
    distributor_id, 
    COUNT(*) AS TOTAL, 
    COUNT(IF(level='exec',1,null)),
    COUNT(IF(level='personal',1,null))
FROM sometable;

COUNT only counts non null values and the DECODE will return non null value 1 only if your condition is satisfied.

Answer 3

For MySQL, this can be shortened to:

SELECT distributor_id,
    COUNT(*) total,
    SUM(level = 'exec') ExecCount,
    SUM(level = 'personal') PersonalCount
FROM yourtable
GROUP BY distributor_id

Answer 4

One way which works for sure

SELECT a.distributor_id,
    (SELECT COUNT(*) FROM myTable WHERE level='personal' and distributor_id = a.distributor_id) as PersonalCount,
    (SELECT COUNT(*) FROM myTable WHERE level='exec' and distributor_id = a.distributor_id) as ExecCount,
    (SELECT COUNT(*) FROM myTable WHERE distributor_id = a.distributor_id) as TotalCount
FROM (SELECT DISTINCT distributor_id FROM myTable) a ;

EDIT:
See @KevinBalmforth's break down of performance for why you likely don't want to use this method and instead should opt for @Taryn♦'s answer. I'm leaving this so people can understand their options.

Answer 5

Well, if you must have it all in one query, you could do a union:

SELECT distributor_id, COUNT() FROM ... UNION
SELECT COUNT() AS EXEC_COUNT FROM ... WHERE level = 'exec' UNION
SELECT COUNT(*) AS PERSONAL_COUNT FROM ... WHERE level = 'personal';

Or, if you can do after processing:

SELECT distributor_id, COUNT(*) FROM ... GROUP BY level;

You will get the count for each level and need to sum them all up to get the total.

Answer 6

I think this can also works for you select count(*) as anc,(select count(*) from Patient where sex='F')as patientF,(select count(*) from Patient where sex='M') as patientM from anc

and also you can select and count related tables like this select count(*) as anc,(select count(*) from Patient where Patient.Id=anc.PatientId)as patientF,(select count(*) from Patient where sex='M') as patientM from anc