Simple example of threading in C++

Answer 1

When searching for an example of a C++ class that calls one of its own instance methods in a new thread, this question comes up, but we were not able to use any of these answers that way. Here's an example that does that:

Class.h

class DataManager
{
public:
    bool hasData;
    void getData();
    bool dataAvailable();
};

Class.cpp

#include "DataManager.h"

void DataManager::getData()
{
    // perform background data munging
    hasData = true;
    // be sure to notify on the main thread
}

bool DataManager::dataAvailable()
{
    if (hasData)
    {
        return true;
    }
    else
    {
        std::thread t(&DataManager::getData, this);
        t.detach(); // as opposed to .join, which runs on the current thread
    }
}

Note that this example doesn't get into mutex or locking.

Answer 2

Create a function that you want the thread to execute, eg:

void task1(std::string msg)
{
    std::cout << "task1 says: " << msg;
}

Now create the thread object that will ultimately invoke the function above like so:

std::thread t1(task1, "Hello");

(You need to #include <thread> to access the std::thread class)

The constructor's arguments are the function the thread will execute, followed by the function's parameters. The thread is automatically started upon construction.

If later on you want to wait for the thread to be done executing the function, call:

t1.join(); 

(Joining means that the thread who invoked the new thread will wait for the new thread to finish execution, before it will continue its own execution).

---

The Code

#include <string>
#include <iostream>
#include <thread>

using namespace std;

// The function we want to execute on the new thread.
void task1(string msg)
{
    cout << "task1 says: " << msg;
}

int main()
{
    // Constructs the new thread and runs it. Does not block execution.
    thread t1(task1, "Hello");

    // Do other things...

    // Makes the main thread wait for the new thread to finish execution, therefore blocks its own execution.
    t1.join();
}

More information about std::thread here

• On GCC, compile with -std=c++0x -pthread.
• This should work for any operating-system, granted your compiler supports this (C++11) feature.

Answer 3

It largely depends on the library you decide to use. For instance, if you use the wxWidgets library, the creation of a thread would look like this:

class RThread : public wxThread {

public:
    RThread()
        : wxThread(wxTHREAD_JOINABLE){
    }
private:
    RThread(const RThread &copy);

public:
    void *Entry(void){
        //Do...

        return 0;
    }

};

wxThread *CreateThread() {
    //Create thread
    wxThread *_hThread = new RThread();

    //Start thread
    _hThread->Create();
    _hThread->Run();

    return _hThread;
}

If your main thread calls the CreateThread method, you'll create a new thread that will start executing the code in your "Entry" method. You'll have to keep a reference to the thread in most cases to join or stop it. More info here: wxThread documentation

Answer 4

#include <thread>
#include <iostream>
#include <vector>
using namespace std;

void doSomething(int id) {
    cout << id << "\n";
}

/**
 * Spawns n threads
 */
void spawnThreads(int n)
{
    std::vector<thread> threads(n);
    // spawn n threads:
    for (int i = 0; i < n; i++) {
        threads[i] = thread(doSomething, i + 1);
    }

    for (auto& th : threads) {
        th.join();
    }
}

int main()
{
    spawnThreads(10);
}

Answer 5

There is also a POSIX library for POSIX operating systems. Check for compatability

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <iostream>

void *task(void *argument){
      char* msg;
      msg = (char*)argument;
      std::cout<<msg<<std::endl;
}

int main(){
    pthread_t thread1, thread2;
    int i1,i2;
    i1 = pthread_create( &thread1, NULL, task, (void*) "thread 1");
    i2 = pthread_create( &thread2, NULL, task, (void*) "thread 2");

    pthread_join(thread1,NULL);
    pthread_join(thread2,NULL);
    return 0;

}

compile with -lpthread

http://en.wikipedia.org/wiki/POSIX_Threads

Answer 6

Well, technically any such object will wind up being built over a C-style thread library because C++ only just specified a stock std::thread model in c++0x, which was just nailed down and hasn't yet been implemented. The problem is somewhat systemic, technically the existing c++ memory model isn't strict enough to allow for well defined semantics for all of the 'happens before' cases. Hans Boehm wrote an paper on the topic a while back and was instrumental in hammering out the c++0x standard on the topic.

http://www.hpl.hp.com/techreports/2004/HPL-2004-209.html

That said there are several cross-platform thread C++ libraries that work just fine in practice. Intel thread building blocks contains a tbb::thread object that closely approximates the c++0x standard and Boost has a boost::thread library that does the same.

http://www.threadingbuildingblocks.org/

http://www.boost.org/doc/libs/1_37_0/doc/html/thread.html

Using boost::thread you'd get something like:

#include <boost/thread.hpp>

void task1() { 
    // do stuff
}

void task2() { 
    // do stuff
}

int main (int argc, char ** argv) {
    using namespace boost; 
    thread thread_1 = thread(task1);
    thread thread_2 = thread(task2);

    // do other stuff
    thread_2.join();
    thread_1.join();
    return 0;
}