I\'m trying to do math from a string.
When I turn a string into a math problem with NSExpression, and then get the result with expressionValue, Swift assumes I want
You might be better off using a 3rd party expression parser/evaluator,
such as DDMathParser.
NSExpression
is quite limited, and has no options to force floating
point evaluation.
If you want to (or have to) stick to NSExpression
: Here is a possible solution to (recursively) replace all constant
values in an expression by their floating point value:
extension NSExpression {
func toFloatingPoint() -> NSExpression {
switch expressionType {
case .constantValue:
if let value = constantValue as? NSNumber {
return NSExpression(forConstantValue: NSNumber(value: value.doubleValue))
}
case .function:
let newArgs = arguments.map { $0.map { $0.toFloatingPoint() } }
return NSExpression(forFunction: operand, selectorName: function, arguments: newArgs)
case .conditional:
return NSExpression(forConditional: predicate, trueExpression: self.true.toFloatingPoint(), falseExpression: self.false.toFloatingPoint())
case .unionSet:
return NSExpression(forUnionSet: left.toFloatingPoint(), with: right.toFloatingPoint())
case .intersectSet:
return NSExpression(forIntersectSet: left.toFloatingPoint(), with: right.toFloatingPoint())
case .minusSet:
return NSExpression(forMinusSet: left.toFloatingPoint(), with: right.toFloatingPoint())
case .subquery:
if let subQuery = collection as? NSExpression {
return NSExpression(forSubquery: subQuery.toFloatingPoint(), usingIteratorVariable: variable, predicate: predicate)
}
case .aggregate:
if let subExpressions = collection as? [NSExpression] {
return NSExpression(forAggregate: subExpressions.map { $0.toFloatingPoint() })
}
case .anyKey:
fatalError("anyKey not yet implemented")
case .block:
fatalError("block not yet implemented")
case .evaluatedObject, .variable, .keyPath:
break // Nothing to do here
}
return self
}
}
Example:
let expression = NSExpression(format: "10/6+3/4")
if let result = expression.toFloatingPoint().expressionValue(with: nil, context: nil) as? Double {
print("result:", result) // 2.41666666666667
}
This works with "simple" expressions using arithmetic operators and functions and some "advanced" expression types (unions, intersections, ...). The remaining conversions can be added if necessary.
Here's a variant of Martin R's great answer that has two important changes:
count({1,2,3,4,5}) / count({1,2})
where the arguments to division aren't constant values.Code:
import Foundation
extension NSExpression {
func toFloatingPointDivision() -> NSExpression {
switch expressionType {
case .function where function == "divide:by:":
guard let args = arguments else { break }
let newArgs = args.map({ arg -> NSExpression in
if arg.expressionType == .constantValue {
if let value = arg.constantValue as? Double {
return NSExpression(forConstantValue: value)
} else {
return arg
}
} else {
return NSExpression(block: { (object, arguments, context) in
// NB: The type of `+[NSExpression expressionForBlock:arguments]` is incorrect.
// It claims the arguments is an array of NSExpressions, but it's not, it's
// actually an array of the evaluated values. We can work around this by going
// through NSArray.
guard let arg = (arguments as NSArray).firstObject else { return NSNull() }
return (arg as? Double) ?? arg
}, arguments: [arg.toFloatingPointDivision()])
}
})
return NSExpression(forFunction: operand, selectorName: function, arguments: newArgs)
case .function:
guard let args = arguments else { break }
let newArgs = args.map({ $0.toFloatingPointDivision() })
return NSExpression(forFunction: operand, selectorName: function, arguments: newArgs)
case .conditional:
return NSExpression(forConditional: predicate,
trueExpression: self.true.toFloatingPointDivision(),
falseExpression: self.false.toFloatingPointDivision())
case .unionSet:
return NSExpression(forUnionSet: left.toFloatingPointDivision(), with: right.toFloatingPointDivision())
case .intersectSet:
return NSExpression(forIntersectSet: left.toFloatingPointDivision(), with: right.toFloatingPointDivision())
case .minusSet:
return NSExpression(forMinusSet: left.toFloatingPointDivision(), with: right.toFloatingPointDivision())
case .subquery:
if let subQuery = collection as? NSExpression {
return NSExpression(forSubquery: subQuery.toFloatingPointDivision(), usingIteratorVariable: variable, predicate: predicate)
}
case .aggregate:
if let subExpressions = collection as? [NSExpression] {
return NSExpression(forAggregate: subExpressions.map({ $0.toFloatingPointDivision() }))
}
case .block:
guard let args = arguments else { break }
let newArgs = args.map({ $0.toFloatingPointDivision() })
return NSExpression(block: expressionBlock, arguments: newArgs)
case .constantValue, .anyKey:
break // Nothing to do here
case .evaluatedObject, .variable, .keyPath:
// FIXME: These should probably be wrapped in blocks like the one
// used in the `.function` case.
break
}
return self
}
}