try/catch with InputMismatchException creates infinite loop

Question

So I\'m building a program which takes ints from user input. I have what seems to be a very straightforward try/catch block which, if the user doesn\'t enter an int, should

Answer 1

You need to call next(); when you get the error. Also it is advisable to use hasNextInt()

       catch (Exception e) {
            System.out.println("Error!");
           input.next();// Move to next other wise exception
        }

Before reading integer value you need to make sure scanner has one. And you will not need exception handling like that.

    Scanner scanner = new Scanner(System.in);
    int n1 = 0, n2 = 0;
    boolean bError = true;
    while (bError) {
        if (scanner.hasNextInt())
            n1 = scanner.nextInt();
        else {
            scanner.next();
            continue;
        }
        if (scanner.hasNextInt())
            n2 = scanner.nextInt();
        else {
            scanner.next();
            continue;
        }
        bError = false;
    }
    System.out.println(n1);
    System.out.println(n2);

Javadoc of Scanner

When a scanner throws an InputMismatchException, the scanner will not pass the token that caused the exception, so that it may be retrieved or skipped via some other method.