Regex pattern to match at least 1 number and 1 character in a string

Question

I have a regex

/^([a-zA-Z0-9]+)$/

this just allows only alphanumerics but also if I insert only number(s) or only

Answer 1

Why not first apply the whole test, and then add individual tests for characters and numbers? Anyway, if you want to do it all in one regexp, use positive lookahead:

/^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$/

Answer 2

If you need the digit to be at the end of any word, this worked for me:

/\b([a-zA-Z]+[0-9]+)\b/g

• \b word boundary
• [a-zA-Z] any letter
• [0-9] any number
• "+" unlimited search (show all results)

Answer 3

And an idea with a negative check.

/^(?!\d*$|[a-z]*$)[a-z\d]+$/i

• ^(?! at start look ahead if string does not
• \d*$ contain only digits | or
• [a-z]*$ contain only letters
• [a-z\d]+$ matches one or more letters or digits until $ end.

Have a look at this regex101 demo

(the i flag turns on caseless matching: a-z matches a-zA-Z)