PHP file_get_contents() returns “failed to open stream: HTTP request failed!”

Question

I am having problems calling a url from PHP code. I need to call a service using a query string from my PHP code. If I type the url into a browser, it works ok, but if I use

Answer 1

Could this be your problem?

Note: If you're opening a URI with special characters, such as spaces, you need to encode the URI with urlencode().

Answer 2

I notice that your URL has spaces in it. I think that usually is a bad thing. Try encoding the URL with

$my_url = urlencode("my url");

and then calling

file_get_contents($my_url);

and see if you have better luck.

Answer 3

I got a similar problem , I parsed the youtube url. The code is;

$json_is = "http://gdata.youtube.com/feeds/api/videos?q=".$this->video_url."&max-results=1&alt=json";
$video_info = json_decode ( file_get_contents ( $json_is ), true );     
$video_title = is_array ( $video_info ) ? $video_info ['feed'] ['entry'] [0] ['title'] ['$t'] : '';

Then I realise that $this->video_url include the whitespace. I solved that using trim($this->video_url).

Maybe it will help you . Good Luck

Answer 4

You basically are required to send some information with the request.

Try this,

$opts = array('http'=>array('header' => "User-Agent:MyAgent/1.0\r\n")); 
//Basically adding headers to the request
$context = stream_context_create($opts);
$html = file_get_contents($url,false,$context);
$html = htmlspecialchars($html);

This worked out for me

Answer 5

file_get_contents() utilizes the fopen() wrappers, therefore it is restricted from accessing URLs through the allow_url_fopen option within php.ini.

You will either need to alter your php.ini to turn this option on or use an alternative method, namely cURL - by far the most popular and, to be honest, standard way to accomplish what you are trying to do.

Answer 6

Use this

file_get_contents($my_url,null,null);