Regex doesn't work in String.matches()

Question

I have this small piece of code

String[] words = {\"{apf\",\"hum_\",\"dkoe\",\"12f\"};
for(String s:words)
{
    if(s.matches(\"[a-z]\"))
    {
        Syste         


        

Answer 1

Welcome to Java's misnamed .matches() method... It tries and matches ALL the input. Unfortunately, other languages have followed suit :(

If you want to see if the regex matches an input text, use a Pattern, a Matcher and the .find() method of the matcher:

Pattern p = Pattern.compile("[a-z]");
Matcher m = p.matcher(inputstring);
if (m.find())
    // match

If what you want is indeed to see if an input only has lowercase letters, you can use .matches(), but you need to match one or more characters: append a + to your character class, as in [a-z]+. Or use ^[a-z]+$ and .find().

Answer 2

java's implementation of regexes try to match the whole string

that's different from perl regexes, which try to find a matching part

if you want to find a string with nothing but lower case characters, use the pattern [a-z]+

if you want to find a string containing at least one lower case character, use the pattern .*[a-z].*

Answer 3

I have faced the same problem once:

Pattern ptr = Pattern.compile("^[a-zA-Z][\\']?[a-zA-Z\\s]+$");

The above failed!

Pattern ptr = Pattern.compile("(^[a-zA-Z][\\']?[a-zA-Z\\s]+$)");

The above worked with pattern within ( and ).

Answer 4

String.matches returns whether the whole string matches the regex, not just any substring.

Answer 5

Your regular expression [a-z] doesn't match dkoe since it only matches Strings of lenght 1. Use something like [a-z]+.

Answer 6

You can make your pattern case insensitive by doing:

Pattern p = Pattern.compile("[a-z]+", Pattern.CASE_INSENSITIVE);