reading lines 2 at a time

Question

Is there a better way to read lines two at a time from a file in python than:

with open(fn) as f:
    for line in f:
        try:
            line2 = f.next(         


        

Answer 1

You could possibly make it more clear with a generator:

def read2(f):
    for line in f:
        try:
            line2 = f.next()
        except StopIteration:
            line2 = ''

        yield line, line2

with open(fn) as f:
    for line1, line2 in read2(f):
        print line1
        print line2

Answer 2

import itertools

with open(fn) as f:
  for line, line2 in itertools.izip_longest(f, f, fillvalue=''):
    print line, line2

Alas, izip_longest requires Python 2.6 or better; 2.5 only has izip, which would truncate the last line if f has an odd number of lines. It's quite easy to supply the equivalent functionality as a generator, of course.

Here's a more general "N at a time" iterator-wrapper:

def natatime(itr, fillvalue=None, n=2):
  return itertools.izip_longest(*(iter(itr),)*n, fillvalue=fillvalue)

itertools is generally the best way to go, but, if you insisted on implementing it by yourself, then:

def natatime_no_itertools(itr, fillvalue=None, n=2):
  x = iter(itr)
  for item in x:
    yield (item,) + tuple(next(x, fillvalue) for _ in xrange(n-1))

In 2.5, I think the best approach is actually not a generator, but another itertools-based solution:

def natatime_25(itr, fillvalue=None, n=2):
  x = itertools.chain(iter(itr), (fillvalue,) * (n-1))
  return itertools.izip(*(x,)*n)

(since 2.5 doesn't have the built-in next, as well as missing izip_longest).

Answer 3

for small to medium sized files,

>>> data=open("file").readlines()
>>> for num,line in enumerate(data[::2]):
...  print ''.join(data[num:num+2])