Python list sort in descending order

Question

How can I sort this list in descending order?

timestamp = [
    \"2010-04-20 10:07:30\",
    \"2010-04-20 10:07:38\",
    \"2010-04-20 10:07:52\",
    \"2010         


        

Answer 1

This will give you a sorted version of the array.

sorted(timestamp, reverse=True)

If you want to sort in-place:

timestamp.sort(reverse=True)

Answer 2

You can simply do this:

timestamp.sort(reverse=True)

Answer 3

Here is another way

timestamp.sort()
timestamp.reverse()
print(timestamp)

Answer 4

you simple type:

timestamp.sort()
timestamp=timestamp[::-1]

Answer 5

In one line, using a lambda:

timestamp.sort(key=lambda x: time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6], reverse=True)

---

Passing a function to list.sort:

def foo(x):
    return time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6]

timestamp.sort(key=foo, reverse=True)

Answer 6

Since your list is already in ascending order, we can simply reverse the list.

>>> timestamp.reverse()
>>> timestamp
['2010-04-20 10:25:38', 
'2010-04-20 10:12:13', 
'2010-04-20 10:12:13', 
'2010-04-20 10:11:50', 
'2010-04-20 10:10:58', 
'2010-04-20 10:10:37', 
'2010-04-20 10:09:46', 
'2010-04-20 10:08:22',
'2010-04-20 10:08:22', 
'2010-04-20 10:07:52', 
'2010-04-20 10:07:38', 
'2010-04-20 10:07:30']