Java regex email

后端 未结 20 2066
清歌不尽
清歌不尽 2020-11-22 13:09

First of all, I know that using regex for email is not recommended but I gotta test this out.

I have this regex:

\\b[A-Z0-9._%-]+@[A-Z0-9.-]+\\.[A-Z]         


        
相关标签:
20条回答
  • 2020-11-22 13:40
    import java.util.Scanner;
    
    public class CheckingTheEmailPassword {
    
        public static void main(String[] args) {
            String email = null;
            String password = null;
            Boolean password_valid = false;
            Boolean email_valid = false;
    
            Scanner input = new Scanner(System.in);
            do {
                System.out.println("Enter your email: ");
                email = input.nextLine();
    
                System.out.println("Enter your passsword: ");
                password = input.nextLine();
    
                // checks for words,numbers before @symbol and between "@" and ".".
                // Checks only 2 or 3 alphabets after "."
                if (email.matches("[\\w]+@[\\w]+\\.[a-zA-Z]{2,3}"))
                    email_valid = true;
                else
                    email_valid = false;
    
                // checks for NOT words,numbers,underscore and whitespace.
                // checks if special characters present
                if ((password.matches(".*[^\\w\\s].*")) &&
                // checks alphabets present
                        (password.matches(".*[a-zA-Z].*")) &&
                        // checks numbers present
                        (password.matches(".*[0-9].*")) &&
                        // checks length
                        (password.length() >= 8))
                    password_valid = true;
                else
                    password_valid = false;
    
                if (password_valid && email_valid)
                    System.out.println(" Welcome User!!");
                else {
                    if (!email_valid)
                        System.out.println(" Re-enter your email: ");
                    if (!password_valid)
                        System.out.println(" Re-enter your password: ");
                }
    
            } while (!email_valid || !password_valid);
    
            input.close();
    
        }
    
    }
    
    0 讨论(0)
  • 2020-11-22 13:41

    FWIW, here is the Java code we use to validate email addresses. The Regexp's are very similar:

    public static final Pattern VALID_EMAIL_ADDRESS_REGEX = 
        Pattern.compile("^[A-Z0-9._%+-]+@[A-Z0-9.-]+\\.[A-Z]{2,6}$", Pattern.CASE_INSENSITIVE);
    
    public static boolean validate(String emailStr) {
            Matcher matcher = VALID_EMAIL_ADDRESS_REGEX.matcher(emailStr);
            return matcher.find();
    }
    

    Works fairly reliably.

    0 讨论(0)
  • 2020-11-22 13:41

    Modification of Armer B. answer which didn't validate emails ending with '.co.uk'

    public static boolean emailValidate(String email) {
        Matcher matcher = Pattern.compile("^([\\w-\\.]+){1,64}@([\\w&&[^_]]+){2,255}(.[a-z]{2,3})+$|^$", Pattern.CASE_INSENSITIVE).matcher(email);
    
        return matcher.find();
    }
    
    0 讨论(0)
  • 2020-11-22 13:43

    Don't. You will never end up with a valid expression.

    For example these are all valid email addresses:

    "Abc\@def"@example.com
    "Fred Bloggs"@example.com
    "Joe\\Blow"@example.com
    "Abc@def"@example.com
    customer/department=shipping@examp­ le.com
    $A12345@example.com
    !def!xyz%abc@example.com
    _somename@example.com
    matteo(this is a comment).corti@example.com
    root@[127.0.0.1]
    

    Just to mention a few problems:

    • you don't consider the many forms of specifying a host (e.g, by the IP address)
    • you miss valid characters
    • you miss non ASCII domain names

    Before even beginning check the corresponding RFCs

    0 讨论(0)
  • 2020-11-22 13:43

    You can use this method for validating email address in java.

    public class EmailValidator {
        private Pattern pattern;
        private Matcher matcher;
    
        private static final String EMAIL_PATTERN = 
            "^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@"
            + "[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";
    
        public EmailValidator() {
            pattern = Pattern.compile(EMAIL_PATTERN);
        }
    
        /**
        * Validate hex with regular expression
        * 
        * @param hex
        *            hex for validation
        * @return true valid hex, false invalid hex
        */
        public boolean validate(final String hex) {
    
        matcher = pattern.matcher(hex);
        return matcher.matches();
    
        }
    }
    
    0 讨论(0)
  • 2020-11-22 13:47

    That's because you are forgetting case insensitivity :

    Pattern regex = Pattern.compile("\\b[\\w.%-]+@[-.\\w]+\\.[A-Za-z]{2,4}\\b");
    

    This matches your example, although it ignores many valid e-mails.

    0 讨论(0)
提交回复
热议问题