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How to sort strings in JavaScript

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生来不讨喜
生来不讨喜 2020-11-22 13:20

I have a list of objects I wish to sort based on a field attr of type string. I tried using -

list.sort(function (a, b) {
    retur
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12条回答
  • 傲寒
    2020-11-22 13:27

    In your operation in your initial question, you are performing the following operation:

    item1.attr - item2.attr

    So, assuming those are numbers (i.e. item1.attr = "1", item2.attr = "2") You still may use the "===" operator (or other strict evaluators) provided that you ensure type. The following should work:

    return parseInt(item1.attr) - parseInt(item2.attr);

    If they are alphaNumeric, then do use localCompare().

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  • 滥情空心
    2020-11-22 13:28 
    list.sort(function(item1, item2){
    return +(item1.attr > item2.attr) || +(item1.attr === item2.attr) - 1;
})

    How they work samples:

    +('aaa'>'bbb')||+('aaa'==='bbb')-1
+(false)||+(false)-1
0||0-1
-1

+('bbb'>'aaa')||+('bbb'==='aaa')-1
+(true)||+(false)-1
1||0-1
1

+('aaa'>'aaa')||+('aaa'==='aaa')-1
+(false)||+(true)-1
0||1-1
0
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  • 忘掉有多难
    2020-11-22 13:28 
    <!doctype html>
<html>
<body>
<p id = "myString">zyxtspqnmdba</p>
<p id = "orderedString"></p>
<script>
var myString = document.getElementById("myString").innerHTML;
orderString(myString);
function orderString(str) {
    var i = 0;
    var myArray = str.split("");
    while (i < str.length){
        var j = i + 1;
        while (j < str.length) {
            if (myArray[j] < myArray[i]){
                var temp = myArray[i];
                myArray[i] = myArray[j];
                myArray[j] = temp;
            }
            j++;
        }
        i++;
    }
    var newString = myArray.join("");
    document.getElementById("orderedString").innerHTML = newString;
}
</script>
</body>
</html>
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  • 一个人的身影
    2020-11-22 13:29

    An explanation of why the approach in the question doesn't work:

    let products = [
    { name: "laptop", price: 800 },
    { name: "phone", price:200},
    { name: "tv", price: 1200}
];
products.sort( (a, b) => {
    {let value= a.name - b.name; console.log(value); return value}
});

> 2 NaN

    Subtraction between strings returns NaN.

    Echoing @Alejadro's answer, the right approach is--

    products.sort( (a,b) => a.name > b.name ? 1 : -1 )

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  • 抹茶落季
    2020-11-22 13:30 
    var str = ['v','a','da','c','k','l']
var b = str.join('').split('').sort().reverse().join('')
console.log(b)
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  • 旧时难觅i
    2020-11-22 13:31

    You should use > or < and == here. So the solution would be:

    list.sort(function(item1, item2) {
    var val1 = item1.attr,
        val2 = item2.attr;
    if (val1 == val2) return 0;
    if (val1 > val2) return 1;
    if (val1 < val2) return -1;
});
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