How do I check if a string contains another string in Swift?

Question

In Objective-C the code to check for a substring in an NSString is:

NSString *string = @\"hello Swift\";
NSRange textRange =[strin         


        

Answer 1

SWIFT 4 is very easy!!

if (yourString.contains("anyThing")) {
   Print("Exist")
}

Answer 2

In Swift 3

if((a.range(of: b!, options: String.CompareOptions.caseInsensitive, range: nil, locale: nil)) != nil){
    print("Done")
}

Answer 3

In Swift 4.2

Use

func contains(_ str: String) -> Bool

Example

let string = "hello Swift"
let containsSwift = string.contains("Swift")
print(containsSwift) // prints true

Answer 4

// Search string exist in employee name finding.
var empName:NSString! = employeeDetails[filterKeyString] as NSString

Case sensitve search.
let rangeOfSearchString:NSRange! = empName.rangeOfString(searchString, options: NSStringCompareOptions.CaseInsensitiveSearch)

// Not found.
if rangeOfSearchString.location != Foundation.NSNotFound
{
    // search string not found in employee name.
}
// Found
else
{
    // search string found in employee name.
}

Answer 5

Here you go! Ready for Xcode 8 and Swift 3.

import UIKit

let mString = "This is a String that contains something to search."
let stringToSearchUpperCase = "String"
let stringToSearchLowerCase = "string"

mString.contains(stringToSearchUpperCase) //true
mString.contains(stringToSearchLowerCase) //false
mString.lowercased().contains(stringToSearchUpperCase) //false
mString.lowercased().contains(stringToSearchLowerCase) //true

Answer 6

In iOS 8 and newer, you can use these two NSString methods:

@availability(iOS, introduced=8.0)
func containsString(aString: String) -> Bool

@availability(iOS, introduced=8.0)
func localizedCaseInsensitiveContainsString(aString: String) -> Bool