tell whether python is in -i mode

Question

How can you tell whether python has been started with the -i flag?

According to the docs, you can check the PYTHONINSPECT variable in os.environ, which is the eq

Answer 1

I took a look at the source, and although the variable set when -i is provided is stored in Py_InteractiveFlag, it doesn't look like it gets exposed to python.

However, if you don't mind getting your hands a bit dirty with some low-level ctypes inspecting, I think you can get at the value by:

import ctypes, os

def interactive_inspect_mode():
    flagPtr = ctypes.cast(ctypes.pythonapi.Py_InteractiveFlag, 
                         ctypes.POINTER(ctypes.c_int))
    return flagPtr.contents.value > 0 or bool(os.environ.get("PYTHONINSPECT",False))

[Edit] fix typo and also check PYTHONINSPECT (which doesn't set the variable), as pointed out in comments.

Answer 2

How to set inspect mode programmatically

The answer from the link @Jweede provided is imprecise. It should be:

import os
os.environ['PYTHONINSPECT'] = '1'

How to retrieve whether interactive/inspect flags are set

Just another variant of @Brian's answer:

import os
from ctypes import POINTER, c_int, cast, pythonapi

def in_interactive_inspect_mode():
    """Whether '-i' option is present or PYTHONINSPECT is not empty."""
    if os.environ.get('PYTHONINSPECT'): return True
    iflag_ptr = cast(pythonapi.Py_InteractiveFlag, POINTER(c_int))
    #NOTE: in Python 2.6+ ctypes.pythonapi.Py_InspectFlag > 0
    #      when PYTHONINSPECT set or '-i' is present 
    return iflag_ptr.contents.value != 0

See the Python's main.c.

Answer 3

This specifies how to programatically switch your script to interactive mode.