Python code:
import xml.etree.ElementTree as ET
root = ET.parse(\"h.xml\")
print root.findall(\'saybye\')
h.xml code:
Element.findall()
finds only elements with a tag which are direct children of the current element.
we need to recursively traversing all childrens to find elements matching your element.
def find_rec(node, element):
def _find_rec(node, element, result):
for el in node.getchildren():
_find_rec(el, element, result)
if node.tag == element:
result.append(node)
res = list()
_find_rec(node, element, res)
return res
Quoting findall,
Element.findall()
finds only elements with a tag which are direct children of the current element.
Since it finds only the direct children, we need to recursively find other children, like this
>>> import xml.etree.ElementTree as ET
>>>
>>> def find_rec(node, element, result):
... for item in node.findall(element):
... result.append(item)
... find_rec(item, element, result)
... return result
...
>>> find_rec(ET.parse("h.xml"), 'saybye', [])
[<Element 'saybye' at 0x7f4fce206710>, <Element 'saybye' at 0x7f4fce206750>, <Element 'saybye' at 0x7f4fce2067d0>]
Even better, make it a generator function, like this
>>> def find_rec(node, element):
... for item in node.findall(element):
... yield item
... for child in find_rec(item, element):
... yield child
...
>>> list(find_rec(ET.parse("h.xml"), 'saybye'))
[<Element 'saybye' at 0x7f4fce206a50>, <Element 'saybye' at 0x7f4fce206ad0>, <Element 'saybye' at 0x7f4fce206b10>]
From version 2.7 on, you can use xml.etree.ElementTree.Element.iter
:
import xml.etree.ElementTree as ET
root = ET.parse("h.xml")
print root.iter('saybye')
See 19.7. xml.etree.ElementTree — The ElementTree XML API
If you aren't afraid of a little XPath, you can use the //
syntax that means find any descendant node:
import xml.etree.ElementTree as ET
root = ET.parse("h.xml")
print root.findall('.//saybye')
Full XPath isn't supported, but here's the list of what is: https://docs.python.org/2/library/xml.etree.elementtree.html#supported-xpath-syntax