Xcode 9 and Xcode 10 giving different results, even with same swift version

Question

I am running this code in both xcode 9.3 and xcode 10 beta 3 playground

import Foundation

public protocol EnumCollection: Hashable {
    static func cases()         


        

Answer 1

The solution for this is below for Xcode 10 and Swift 4.2 and above.

Step 1: Create Protocol EnumIterable.

protocol EnumIterable: RawRepresentable, CaseIterable {
    var indexValue: Int { get }
}

extension EnumIterable where Self.RawValue: Equatable {
    var indexValue: Int {
        var index = -1
        let cases = Self.allCases as? [Self] ?? []
        for (caseIndex, caseItem) in cases.enumerated() {
            if caseItem.rawValue == self.rawValue {
                index = caseIndex
                break
            }
        }
        return index
    }
}

Step 2: Extend EnumIterator Protocol to your enums.

enum Colors: String, EnumIterable {
    case red = "Red"
    case yellow = "Yellow"
    case blue = "Blue"
    case green = "Green"
}

Step 3: Use indexValue property like using hashValue.

Colors.red.indexValue
Colors.yellow.indexValue
Colors.blue.indexValue
Colors.green.indexValue

Sample Print statement and Output

print("Index Value: \(Colors.red.indexValue), Raw Value: \(Colors.red.rawValue), Hash Value: \(Colors.red.hashValue)")

Output: "Index Value: 0, Raw Value: Red, Hash Value: 1593214705812839748"

print("Index Value: \(Colors.yellow.indexValue), Raw Value: \(Colors.yellow.rawValue), Hash Value: \(Colors.yellow.hashValue)")

Output: "Index Value: 1, Raw Value: Yellow, Hash Value: -6836447220368660818"

print("Index Value: \(Colors.blue.indexValue), Raw Value: \(Colors.blue.rawValue), Hash Value: \(Colors.blue.hashValue)")

Output: "Index Value: 2, Raw Value: Blue, Hash Value: -8548080225654293616"

print("Index Value: \(Colors.green.indexValue), Raw Value: \(Colors.green.rawValue), Hash Value: \(Colors.green.hashValue)") 

Output: "Index Value: 3, Raw Value: Green, Hash Value: 6055121617320138804"

Answer 2

If you use hashValue of an enum to determine case values (position or id), it's a wrong approach since it doesn't guarantee to return sequential int values, 0,1,2... It is not working anymore from swift 4.2

For example, If you use an enum like this :

enum AlertResultType {
    case ok, cancel 
}

hashValue of this enum might return a large int value instead of 0 (ok) and 1 (cancel).

So you may need to declare the enum type more precisely and use rowValue. For example

enum AlertResultType : Int {
    case ok = 0, cancel = 1
}

Answer 3

That is an undocumented way to get a sequence of all enumeration values, and worked only by chance with earlier Swift versions. It relies on the hash values of the enumeration values being consecutive integers, starting at zero.

That definitely does not work anymore with Swift 4.2 (even if running in Swift 4 compatibility mode) because hash values are now always randomized, see SE-0206 Hashable Enhancements:

To make hash values less predictable, the standard hash function uses a per-execution random seed by default.

You can verify that with

print(NumberEnum.one.hashValue)
print(NumberEnum.two.hashValue)

which does not print 0 and 1 with Xcode 10, but some other values which also vary with each program run.

For a proper Swift 4.2/Xcode 10 solution, see How to enumerate an enum with String type?:

extension NumberEnum: CaseIterable  { }
print(Array(NumberEnum.allCases).count) // 4