Random.Next returns always the same values [duplicate]

Answer 1

Use a single, static Random number generator for all instances of the class.

class a
{
  private static Random rnd;
  static a() {
      rnd = new Random();
  }
  private void Count()
  {
    int r1 = rnd.Next(-1, 2);
    int r2 = rnd.Next(-1, 2);
  }
}

Note the change to give you numbers in the range -1,1 rather than -1,0

Answer 2

You're creating a new instance of Random very close together (your loop is very tight) so each instance is effectively using the same seed value.

A better approach would be to create one instance and pass that to your Count method.

You problably know this next bit, but I'll include it here for completeness:

The MSDN has the details on this, but basically your problem is the Random.Next method you're using generates:

A 32-bit signed integer greater than or equal to minValue and less than maxValue; that is, the range of return values includes minValue but not maxValue. If minValue equals maxValue, minValue is returned.

because of this your calls will return -1 or 0.

Answer 3

The problem is that you are creating instances of the Random class too close in time.

When you create a Random object, it's seeded with a value from the system clock. If you create Random instances too close in time, they will all be seeded with the same random sequence.

Create a single Random object and pass its reference to the constructor when you create instances of the "a" class, instead of creating one Random object for each "a" instance.

Answer 4

You include a random instance for each A instance. It sounds like they're all getting the same default seed value. You probably want to make a static random for all A instances and use it repeatedly, or alternatively provide a seed value to the Random() instance in the A constructor.