MySQL 'Order By' - sorting alphanumeric correctly

Question

I want to sort the following data items in the order they are presented below (numbers 1-12):

1
2
3
4
5
6
7
8
9
10
11
12

However, my query - using

Answer 1

This is a simple example.

SELECT HEX(some_col) h        
FROM some_table 
ORDER BY h

Answer 2

This type of question has been asked previously.

The type of sorting you are talking about is called "Natural Sorting". The data on which you want to do sort is alphanumeric. It would be better to create a new column for sorting.

For further help check natural-sort-in-mysql

Answer 3

SELECT length(actual_project_name),actual_project_name,
SUBSTRING_INDEX(actual_project_name,'-',1) as aaaaaa,
SUBSTRING_INDEX(actual_project_name, '-', -1) as actual_project_number,
concat(SUBSTRING_INDEX(actual_project_name,'-',1),SUBSTRING_INDEX(actual_project_name, '-', -1)) as a
FROM ctts.test22 
order by 
SUBSTRING_INDEX(actual_project_name,'-',1) asc,cast(SUBSTRING_INDEX(actual_project_name, '-', -1) as unsigned) asc

Answer 4

SELECT s.id, s.name, LENGTH(s.name) len, ASCII(s.name) ASCCCI FROM table_name s ORDER BY ASCCCI,len,NAME ASC;

Answer 5

This should sort alphanumeric field like: 1/ Number only, order by 1,2,3,4,5,6,7,8,9,10,11 etc... 2/ Then field with text like: 1foo, 2bar, aaa11aa, aaa22aa, b5452 etc...

SELECT  MyField
FROM MyTable
order by 
    IF( MyField REGEXP '^-?[0-9]+$' = 0, 
    9999999999 ,  
    CAST(MyField AS DECIMAL) 
    ), MyField

The query check if the data is a number, if not put it to 9999999999 , then order first on this column, then order on data with text

Good luck!

Answer 6

This works for type of data: Data1, Data2, Data3 ......,Data21. Means "Data" String is common in all rows.

For ORDER BY ASC it will sort perfectly, For ORDER BY DESC not suitable.

SELECT * FROM table_name ORDER BY LENGTH(column_name), column_name ASC;