I have a long Hex string that represents a series of values of different types. I wish to convert this Hex String into a byte array so that I can shift each value out and co
You can use the Codecs module in the Python Standard Library, i.e.
import codecs
codecs.decode(hexstring, 'hex_codec')
def hex2bin(s):
hex_table = ['0000', '0001', '0010', '0011',
'0100', '0101', '0110', '0111',
'1000', '1001', '1010', '1011',
'1100', '1101', '1110', '1111']
bits = ''
for i in range(len(s)):
bits += hex_table[int(s[i], base=16)]
return bits
Assuming you have a byte string like so
"\x12\x45\x00\xAB"
and you know the amount of bytes and their type you can also use this approach
import struct
bytes = '\x12\x45\x00\xAB'
val = struct.unpack('<BBH', bytes)
#val = (18, 69, 43776)
As I specified little endian (using the '<' char) at the start of the format string the function returned the decimal equivalent.
0x12 = 18
0x45 = 69
0xAB00 = 43776
B is equal to one byte (8 bit) unsigned
H is equal to two bytes (16 bit) unsigned
More available characters and byte sizes can be found here
The advantages are..
You can specify more than one byte and the endian of the values
Disadvantages..
You really need to know the type and length of data your dealing with
provided I understood correctly, you should look for binascii.unhexlify
import binascii
a='45222e'
s=binascii.unhexlify(a)
b=[ord(x) for x in s]
You should be able to build a string holding the binary data using something like:
data = "fef0babe"
bits = ""
for x in xrange(0, len(data), 2)
bits += chr(int(data[x:x+2], 16))
This is probably not the fastest way (many string appends), but quite simple using only core Python.
Suppose your hex string is something like
>>> hex_string = "deadbeef"
>>> hex_data = hex_string.decode("hex")
>>> hex_data
"\xde\xad\xbe\xef"
>>> bytes.fromhex(hex_string) # Python ≥ 3
b'\xde\xad\xbe\xef'
>>> bytearray.fromhex(hex_string)
bytearray(b'\xde\xad\xbe\xef')
Note that bytes
is an immutable version of bytearray
.