Is there a way to expand a Python tuple into a function - as actual parameters?
For example, here expand()
does the magic:
some_tuple =
Similar to @Dominykas's answer, this is a decorator that converts multiargument-accepting functions into tuple-accepting functions:
apply_tuple = lambda f: lambda args: f(*args)
Example 1:
def add(a, b):
return a + b
three = apply_tuple(add)((1, 2))
Example 2:
@apply_tuple
def add(a, b):
return a + b
three = add((1, 2))
Note that you can also expand part of argument list:
myfun(1, *("foo", "bar"))
myfun(*some_tuple)
does exactly what you request. The *
operator simply unpacks the tuple (or any iterable) and passes them as the positional arguments to the function. Read more about unpacking arguments.
Take a look at the Python tutorial section 4.7.3 and 4.7.4. It talks about passing tuples as arguments.
I would also consider using named parameters (and passing a dictionary) instead of using a tuple and passing a sequence. I find the use of positional arguments to be a bad practice when the positions are not intuitive or there are multiple parameters.
This is the functional programming method. It lifts the tuple expansion feature out of syntax sugar:
apply_tuple = lambda f, t: f(*t)
Redefine apply_tuple
via curry to save a lot of partial
calls in the long run:
from toolz import curry
apply_tuple = curry(apply_tuple)
Example usage:
from operator import add, eq
from toolz import thread_last
thread_last(
[(1,2), (3,4)],
(map, apply_tuple(add)),
list,
(eq, [3, 7])
)
# Prints 'True'