TSQL Calculate week number of the month

Question

I want to calculate the week number of the month,I want to calculate the week number whether its odd or even week how can I get this in TSQL ? Thanks all!

Answer 1

Try this:

SELECT (DATEPART(d, '02/07/2011')/7)%2 AS WeekNo, --Replace your date column in place of '02/07/2011'
       CASE (DATEPART(d, '02/07/2011')/7)%2 
                WHEN 1 THEN 'Odd' 
                ELSE 'Even'
             END AS WeekType

Answer 2

I think this makes the approach very obvious:

DECLARE @DayOne DATETIME
DECLARE @ThisDay DATETIME
SET @ThisDay = GETDATE()
SET @DayOne = CAST(CAST(MONTH(@ThisDay) AS VARCHAR) + '/1/' + CAST(YEAR(@ThisDay) AS VARCHAR) AS DATETIME)
SELECT (DATEPART(wk, @ThisDay) - DATEPART(wk, @DayOne) + 1) AS [Week Of Month]

SQL Server 2012 has a CONCAT function that can be used to more easily build the DayOne string:

DECLARE @DayOne DATETIME
DECLARE @ThisDay DATETIME
SET @ThisDay = GETDATE()
SET @DayOne = CAST(CONCAT(MONTH(@ThisDay), '/1/', YEAR(@ThisDay)) AS DATETIME)
SELECT (DATEPART(wk, @ThisDay) - DATEPART(wk, @DayOne) + 1) AS [Week Of Month]

Answer 3

This gives you the week of the date @dt within its month. There is a 2nd column that uses a CASE statement over the expression, to show either "Odd" or "Even"

declare @dt datetime
set @dt = GETDATE()

select
    WhichWeekOfMonth = datepart(wk, @dt)
                     - datepart(wk,dateadd(m, DATEDIFF(M, 0, @dt), 0)) + 1,
    case when (datepart(wk, @dt)
            - datepart(wk,dateadd(m, DATEDIFF(M, 0, @dt), 0)) + 1) % 2 = 1
         then 'Odd' else 'Even' end

Answer 4

How about something readable, easily customizable, and predictable...

DECLARE @dayOfMonth AS INT;
SET @dayOfMonth = DATEPART(DAY, '3/14/2013');
SELECT CASE 
    WHEN @dayOfMonth < 8 THEN 1
    WHEN @dayOfMonth < 15 THEN 2
    WHEN @dayOfMonth < 22 THEN 3
    ELSE 4
END AS weekOfMonth;

Answer 5

It will give you week Number for Every month

declare @dates datetime
select @dates='2011-03-22'
SELECT datepart(dd,@dates), ceiling (cast(datepart(dd,@dates)as numeric(38,8))/7)