TypeError: 'module' object is not callable

Question

File \"C:\\Users\\Administrator\\Documents\\Mibot\\oops\\blinkserv.py\", line 82, in __init__
    self.serv = socket(AF_INET,SOCK_STREAM)
TypeError: \'module\' objec         


        

Answer 1

Add to the main __init__.py in YourClassParentDir, e.g.:

from .YourClass import YourClass

Then, you will have an instance of your class ready when you import it into another script:

from YourClassParentDir import YourClass

Answer 2

socket is a module, containing the class socket.

You need to do socket.socket(...) or from socket import socket:

>>> import socket
>>> socket
<module 'socket' from 'C:\Python27\lib\socket.pyc'>
>>> socket.socket
<class 'socket._socketobject'>
>>>
>>> from socket import socket
>>> socket
<class 'socket._socketobject'>

This is what the error message means:
It says module object is not callable, because your code is calling a module object. A module object is the type of thing you get when you import a module. What you were trying to do is to call a class object within the module object that happens to have the same name as the module that contains it.

Here is a way to logically break down this sort of error:

• "module object is not callable. Python is telling me my code trying to call something that cannot be called. What is my code trying to call?"
• "The code is trying to call on socket. That should be callable! Is the variable socket is what I think it is?`
• I should print out what socket is and check print socket

Answer 3

Assume that the content of YourClass.py is:

class YourClass:
    # ......

If you use:

from YourClassParentDir import YourClass  # means YourClass.py

In this way, I got TypeError: 'module' object is not callable if you then tried to use YourClass().

But, if you use:

from YourClassParentDir.YourClass import YourClass   # means Class YourClass

or use YourClass.YourClass(), it works for me.

Answer 4

A simple way to solve this problem is export thePYTHONPATH variable enviroment. For example, for Python 2.6 in Debian/GNU Linux:

export PYTHONPATH=/usr/lib/python2.6`

In other operating systems, you would first find the location of this module or the socket.py file.

Answer 5

Here is another gotcha, that took me awhile to see even after reading these posts. I was setting up a script to call my python bin scripts. I was getting the module not callable too.

My zig was that I was doing the following:

from mypackage.bin import myscript
...
myscript(...)

when my zag needed to do the following:

from mypackage.bin.myscript import myscript
...
myscript(...)

In summary, double check your package and module nesting.

What I am trying to do is have a scripts directory that does not have the *.py extension, and still have the 'bin' modules to be in mypackage/bin and these have my *.py extension. I am new to packaging, and trying to follow the standards as I am interpreting them. So, I have at the setup root:

setup.py
scripts/
      script1
mypackage/
   bin/
      script1.py
   subpackage1/
   subpackage_etc/

If this is not compliant with standard, please let me know.

Answer 6

I guess you have overridden the builtin function/variable or something else "module" by setting the global variable "module". just print the module see whats in it.