MySQL: select date of current week's monday

Question

I\'m building a weekly report using MySQL queries. First I get week number by

SELECT WEEK(CURDATE());

Then I need to displ

Answer 1

SELECT DATE_ADD((SELECT curdate() - INTERVAL (WEEKDAY(curdate())+1)DAY),INTERVAL 1 DAY) as current_monday

Answer 2

For thhose who need the Monday date of the current week.

If you count Monday as the first day of the week:

SELECT STR_TO_DATE(CONCAT(YEARWEEK(NOW(), 1),'Monday'), '%x%v %W');

If you count Sunday as the first day of the week:

SELECT STR_TO_DATE(CONCAT(YEARWEEK(NOW()),'Monday'), '%X%V %W');

Answer 3

You can use this:

<?php 
    $week = date('W');
    $year = date('Y');
    echo $date1 = date(
        'Y-m-d', 
        strtotime($year . 'W' . str_pad($week, 2, '0', STR_PAD_LEFT))
    );
    ?>

Answer 4

If you need date of monday in current week try this:

SELECT DATE_ADD(CURDATE(), INTERVAL - WEEKDAY(CURDATE()) DAY)

It return you monday date of current week.

Answer 5

In fact, we substruct days, not add them. Just more simple expression:

DATE_SUB( CURDATE(), INTERVAL WEEKDAY( CURDATE() )

Answer 6

-- current week monday
 (SELECT DATE_ADD(CURDATE(), INTERVAL - WEEKDAY(CURDATE()) DAY)) 

-- current week friday  
SELECT DATE_ADD((SELECT DATE_ADD(CURDATE(), INTERVAL - WEEKDAY(CURDATE()) DAY)),INTERVAL 4 DAY);

-- next week monday 
SELECT date(curdate() - interval weekday(curdate()) day + interval 1 week);

-- next week friday 
SELECT DATE_ADD((SELECT date(curdate() - interval weekday(curdate()) day + interval 1 week)),INTERVAL 4 DAY);