Sort array by firstname (alphabetically) in Javascript

Question

I got an array (see below for one object in the array) that I need to sort by firstname using JavaScript. How can I do it?

var user = {
   bio: null,
   emai         


        

Answer 1

in simply words you can use this method

users.sort(function(a,b){return a.firstname < b.firstname ? -1 : 1});

Answer 2

You can use this for objects

transform(array: any[], field: string): any[] {
return array.sort((a, b) => a[field].toLowerCase() !== b[field].toLowerCase() ? a[field].toLowerCase() < b[field].toLowerCase() ? -1 : 1 : 0);}

Answer 3

You can use the in-built array method - sort. This method takes a callback method as a param

    // custom sort function to be passed as param/callback to the Array's sort method
    function myCustomSort(a, b) {
        return (a.toLowerCase() > b.toLowerCase()) ? 1 : -1;
    }

    // Actual method to be called by entity that needs sorting feature
    function sortStrings() {
        var op = Array.prototype.sort.call(arguments, myCustomSort);
    }

    // Testing the implementation
    var sortedArray = sortStrings("Burger", "Mayo1", "Pizza", "boxes", "Apples", "Mayo");
    console.log(sortedArray); //["Apples", "boxes", "Burger", "Mayo", "Mayo1", "Pizza"]

Key Points to be noted for understanding this code.

1. The custom method, in this case, myCustomSort, should return +1 or -1 for each element pair(from the input array) comparison.
2. Use toLowerCase()/toUpperCase() in the custom sorting callback method so that case difference does not affect the correctness of the sorting process.

I hope this is clear enough explanation. Feel free to comment if you think, more info is needed.

Cheers!

Answer 4

Nice little ES6 one liner:

users.sort((a, b) => a.firstname !== b.firstname ? a.firstname < b.firstname ? -1 : 1 : 0);

Answer 5

A more compact notation:

user.sort(function(a, b){
    return a.firstname === b.firstname ? 0 : a.firstname < b.firstname ? -1 : 1;
})