Create multiple numbered variables based on a int

Question

How would I create a number of NSDictionary variables using an array\'s count?

This is basically what I came up with, but I\'m not sure how to make this

Answer 1

You need to create a mutable array, and then put the objects into the array. You can't create a variable with the same name as the contents of a string, as you have done. For example:

NSMutableArray *arr = [[NSMutableArray alloc] initWithCapacity:[doesntContainAnother count]];
int i = 0;    // Note: type is int, not int*
for (i = 0; i < [doesntCountainAnother count]; i++) {
    [arr addObject:[NSMutableDictionary dictionary]];
}

// Later...
NSMutableDictionary *d1 = [arr objectAtIndex:3];

Or if you want to pull them out of the list by name:

NSMutableDictionary *dict = [[NSMutableDictionary alloc] initWithCapacity:[doesntCountainAnother count]];
int i = 0;
for (i = 0; i < [doesntContainAnother count]; i++) {
    [dict setObject:[NSMutableDictionary dictionary] forKey:[NSString stringWithFormat:@"loopDictionary%d", i]];
}

// Later...
NSMutableDictionary *d1 = [dict objectForKey:@"loopDictionary3"];

But the first way is likely the easiest.

Answer 2

Create a mutable array and loop until you reach the original array's count, creating a dictionary and adding it to the mutable array on each iteration.

Your code should look like this.

NSMutableArray *dictionaries = [[NSMutableArray alloc] init];
for (int i = 0; i < doesntContainAnother.count; i++) {
    [dictionaries addObject:[NSMutableDictionary dictionaryWithObject:[array1 objectAtIndex:i] forKey:[array2 objectAtIndex:i]]];
}

The approach of creating variables with numbers at the end of their names is an antipattern and not even possible in Objective-C. It's equivalent to an array, but clunkier.