Background:
I built an installer for my app, and all my dll\'s and content files are getting correctly copied to the C:\\Program Files\\MyComp
If you want to get the path to the directory under which your executable runs, you should not rely on the Environment.CurrentDirectory, since it can be changed in a number of ways (shotrtcut settings, etc). Try one of these options instead:
System.IO.Path.GetDirectoryName(Application.ExecutablePath);
or
System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetEntryAssembly().Location);
When a program is started, the current directory is typically the same as the one of the starting application, unless the starting application specifies a different working directory. It can really be anywhere on disk.
In your case, the starting application is the shell (explorer.exe) in both cases. It does specify a working directory when starting a program, depending on the context of the launch. You have seen two different cases (double-clicking on a file in explorer, and running from the start menu); you have also found what Microsoft considers the most sensible values for current directory in either case: the user's home directory, and the directory that is shown in explorer (respectively).
Use Application.StartupPath
instead of Environment.CurrentDirectory
.
I've had a similar problem, where the CurrentDirectory
was being changed inadvertently by something like an OpenFileDialog
without me even realizing it.
In your case, it sounds like the process that you're starting the application form is changing the CurrentDirectory
unbeknownst to you.
The Environment.CurrentDirectory
contains current directory that is really current directory now. The value depends on many factors. Any application may change the value. This value doesn't concerned with your application only.
If you want to get the start up directory then use Application.StartupPath
.
Since you said that your application is using WPF, you can use the code below instead of Application.StartupPath :
String appPath = System.IO.Path.GetDirectoryName(Process.GetCurrentProcess().MainModule.FileName);