How to do if pattern matching with multiple cases?

Question

I\'m searching for the syntax to do pattern matching with multiple cases in an if case statement. The example would be this:

enum Gender {
    case Male, Fem         


        

Answer 1

For pattern matching, what you describe will not work yet. You could do this in your case. But if it cannot be convert into a hashValue. Then this would not work either.

// Using Pattern Matching for more than one case.
if case 0...2 = a.hashValue {
    print("Hello")
}

//Normal if else
if a == .Male || a == .Female {
    print("Hello")
}

Answer 2

You should use a collection. In JavaScript I would write something like this:

if ([Gender.Male, Gender.Female].includes(actualGender))
    console.log(actualGender);

Note that I have not a clue about swift, or how to do the same in that language, so here is a relevant answer in the topic: https://stackoverflow.com/a/25391725/607033 :D

EDIT: This is the Swift version:

if [.Male, .Female].contains(a) {

}

Answer 3

A simple array does the trick:

if [.Male, .Female].contains(a) {
    print("Male or female")
} else {
    print("Transgender")
}

I'm simply amazed at Swift's ability to infer type. Here, it gets that .Male and .Female are of type gender from a.