Extract time from datetime and determine if time (not date) falls within range?

Question

The problem is that I want it to ignore the date and only factor in the time. Here is what I have:

import time
from time import mktime
from datetime import d         


        

Answer 1

This line:

str_time = datetime.strptime(Datetime, "%m/%j/%y %H:%M")

returns a datetime object as per the docs.

You can test this yourself by running the following command interactively in the interpreter:

>>> import datetime
>>> datetime.datetime.strptime('12/31/13 00:12', "%m/%j/%y %H:%M")
datetime.datetime(2013, 1, 31, 0, 12)
>>>

The time portion of the returned datetime can then be accessed using the .time() method.

>>> datetime.datetime.strptime('12/31/13 00:12', "%m/%j/%y %H:%M").time()
datetime.time(0, 12)
>>>

The datetime.time() result can then be used in your time comparisons.

Answer 2

Use this only gives you time.

from datetime import datetime

now = datetime.now()
current_time = now.strftime("%H:%M:%S")
print("Current Time =", current_time)