How do you Programmatically Download a Webpage in Java

Question

I would like to be able to fetch a web page\'s html and save it to a String, so I can do some processing on it. Also, how could I handle various types of compr

Answer 1

All the above mentioned approaches do not download the web page text as it looks in the browser. these days a lot of data is loaded into browsers through scripts in html pages. none of above mentioned techniques supports scripts, they just downloads the html text only. HTMLUNIT supports the javascripts. so if you are looking to download the web page text as it looks in the browser then you should use HTMLUNIT.

Answer 2

You'd most likely need to extract code from a secure web page (https protocol). In the following example, the html file is being saved into c:\temp\filename.html Enjoy!

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.URL;

import javax.net.ssl.HttpsURLConnection;

/**
 * <b>Get the Html source from the secure url </b>
 */
public class HttpsClientUtil {
    public static void main(String[] args) throws Exception {
        String httpsURL = "https://stackoverflow.com";
        String FILENAME = "c:\\temp\\filename.html";
        BufferedWriter bw = new BufferedWriter(new FileWriter(FILENAME));
        URL myurl = new URL(httpsURL);
        HttpsURLConnection con = (HttpsURLConnection) myurl.openConnection();
        con.setRequestProperty ( "User-Agent", "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:63.0) Gecko/20100101 Firefox/63.0" );
        InputStream ins = con.getInputStream();
        InputStreamReader isr = new InputStreamReader(ins, "Windows-1252");
        BufferedReader in = new BufferedReader(isr);
        String inputLine;

        // Write each line into the file
        while ((inputLine = in.readLine()) != null) {
            System.out.println(inputLine);
            bw.write(inputLine);
        }
        in.close(); 
        bw.close();
    }
}

Answer 3

Get help from this class it get code and filter some information.

public class MainActivity extends AppCompatActivity {

    EditText url;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate( savedInstanceState );
        setContentView( R.layout.activity_main );

        url = ((EditText)findViewById( R.id.editText));
        DownloadCode obj = new DownloadCode();

        try {
            String des=" ";

            String tag1= "<div class=\"description\">";
            String l = obj.execute( "http://www.nu.edu.pk/Campus/Chiniot-Faisalabad/Faculty" ).get();

            url.setText( l );
            url.setText( " " );

            String[] t1 = l.split(tag1);
            String[] t2 = t1[0].split( "</div>" );
            url.setText( t2[0] );

        }
        catch (Exception e)
        {
            Toast.makeText( this,e.toString(),Toast.LENGTH_SHORT ).show();
        }

    }
                                        // input, extrafunctionrunparallel, output
    class DownloadCode extends AsyncTask<String,Void,String>
    {
        @Override
        protected String doInBackground(String... WebAddress) // string of webAddress separate by ','
        {
            String htmlcontent = " ";
            try {
                URL url = new URL( WebAddress[0] );
                HttpURLConnection c = (HttpURLConnection) url.openConnection();
                c.connect();
                InputStream input = c.getInputStream();
                int data;
                InputStreamReader reader = new InputStreamReader( input );

                data = reader.read();

                while (data != -1)
                {
                    char content = (char) data;
                    htmlcontent+=content;
                    data = reader.read();
                }
            }
            catch (Exception e)
            {
                Log.i("Status : ",e.toString());
            }
            return htmlcontent;
        }
    }
}

Answer 4

Jetty has an HTTP client which can be use to download a web page.

package com.zetcode;

import org.eclipse.jetty.client.HttpClient;
import org.eclipse.jetty.client.api.ContentResponse;

public class ReadWebPageEx5 {

    public static void main(String[] args) throws Exception {

        HttpClient client = null;

        try {

            client = new HttpClient();
            client.start();

            String url = "http://www.something.com";

            ContentResponse res = client.GET(url);

            System.out.println(res.getContentAsString());

        } finally {

            if (client != null) {

                client.stop();
            }
        }
    }
}

The example prints the contents of a simple web page.

In a Reading a web page in Java tutorial I have written six examples of dowloading a web page programmaticaly in Java using URL, JSoup, HtmlCleaner, Apache HttpClient, Jetty HttpClient, and HtmlUnit.

Answer 5

To do so using NIO.2 powerful Files.copy(InputStream in, Path target):

URL url = new URL( "http://download.me/" );
Files.copy( url.openStream(), Paths.get("downloaded.html" ) );

Answer 6

I'd use a decent HTML parser like Jsoup. It's then as easy as:

String html = Jsoup.connect("http://stackoverflow.com").get().html();

It handles GZIP and chunked responses and character encoding fully transparently. It offers more advantages as well, like HTML traversing and manipulation by CSS selectors like as jQuery can do. You only have to grab it as Document, not as a String.

Document document = Jsoup.connect("http://google.com").get();

You really don't want to run basic String methods or even regex on HTML to process it.

See also:

• What are the pros and cons of leading HTML parsers in Java?