Function to create in-memory zip file and return as http response

Question

I am avoiding the creation of files on disk, this is what I have got so far:

def get_zip(request):
    import zipfile, StringIO
    i = open(\'picture.jpg\',         


        

Answer 1

For StringIO you should generally use o.getvalue() to get the result. Also, if you want to add a normal file to the zip file, you can use zf.write('picture.jpg'). You don't need to manually read it.

Answer 2

Avoiding disk files can slow your server to a crawl, but it will certainly work.

You'll exhaust memory if you serve too many of these requests concurrently.