Converting exponential value in java to a number format

Question

I am trying to read the values from excel sheet using java. When i type more than 10 letters in a cell in excel it is displaying in exponential form like \"9.78313E+2\". but

Answer 1

You can use BigDecimal, if you want the exact value that you have in Excel Sheet: -

BigDecimal bd = new BigDecimal("4256411411");
System.out.println(bd.doubleValue());

// If you are sure that's not a floating point number, then use
System.out.println(bd.longValue());  

Prints: -

4.256411411E9  
4256411411

Answer 2

You can also use wrapper classes :

Double bd=new Double(4445566622);
System.out.println(bd.longValue());

Outputs -4445566622

Answer 3

i had same problem when i only needed String Data that is "1744949451" but it give "1.744949451E9" so this worked for me

          XSSFCell cell = cells.getCell(j);
          String value = cell.toString();
          if (cell.getCellType() == XSSFCell.CELL_TYPE_NUMERIC) {
            //cell.setCellType(XSSFCell.CELL_TYPE_STRING);
            value = cell.getRawValue();
          }
          Log.i("LOG", value + " " + cell.getCellType());

Answer 4

Try the following pattern:

Double dblValue = Double.parseDouble("1.99E+07");       
String str = String.format("%.2f", dblValue);
System.out.println(str);

Output:

run:
19900000,00
BUILD SUCCESSFUL (total time: 0 seconds)

Answer 5

You can convert as follows, for example:

new BigDecimal("406770000244E+12").toBigInteger();

Answer 6

You can convert easily with the following methods:

Double.valueOf("9.78313E+2").longValue() or

BigDecimal bd = new BigDecimal("9.78313E+2");
long val = bd.longValue();

Assuming that the given number is in a String form.