How to handle StackOverflowError in Java? [closed]

Answer 1

As mentioned by many in this thread, the common cause for this is a recursive method call that doesn't terminate. Where possible avoid the stack overflow and if you this in testing you should consider this in most cases to be a serious bug. In some cases you can configure the thread stack size in Java to be larger to handle some circumstances ( large data sets being managed in local stack storage, long recursive calls) but this will increase the overall memory footprint which can lead to issues in the number of threads available in the VM. Generally if you get this exception the thread and any local data to this thread should be considered toast and not used( ie suspect and possibly corrupt).

Answer 2

Simple,

Look at the stack trace that the StackOverflowError produces so you know where in your code it occurs and use it to figure out how to rewrite your code so that it doesn't call itself recursively (the likely cause of your error) so it won't happen again.

StackOverflowErrors are not something that needs to be handled via a try...catch clause but it points to a basic flaw in the logic of your code that needs to be fixed by you.

Answer 3

/*
Using Throwable we can trap any know error in JAVA..
*/
public class TestRecur {
    private int i = 0;


    public static void main(String[] args) {
        try {
            new TestRecur().show();
        } catch (Throwable err) {
            System.err.println("Error...");
        }
    }

    private void show() {
        System.out.println("I = " + i++);
        show();
    }
}

However you may have a look at the link: http://marxsoftware.blogspot.in/2009/07/diagnosing-and-resolving.html to understand the code snippet, which may raise error

Answer 4

StackOverFlow Error - when you create a method in java at the time some size of memory allocation will be allocated in the stack memory. if you create a method inside the infinite loop then memory allocation will be created 'n' times. When memory allocation is exceeding then the error will occur. The error is called a StackOverFlow error.

If you want to avoid this error please consider stack memory size during implementation from the beginning.

Answer 5

I'm not sure what you mean with "handle".

You can certainly catch that error:

public class Example {
    public static void endless() {
        endless();
    }

    public static void main(String args[]) {
        try {
            endless();
        } catch(StackOverflowError t) {
            // more general: catch(Error t)
            // anything: catch(Throwable t)
            System.out.println("Caught "+t);
            t.printStackTrace();
        }
        System.out.println("After the error...");
    }
}

but that is most likely a bad idea, unless you know exactly what you are doing.

Answer 6

in some occasion, you can't catch stackoverflowerror. whenever you try, you will encounter new one. because is java vm. it's good to find recursive code blocks, like Andrew Bullock's said.