In the below example, userids
is my reference data frame and userdata
is the data frame where the replacements should take place.
&
Here a try using sqldf
to get the result as a multiple join on differents columns.
library(sqldf)
sqldf('SELECT d.INFO,d.AGE,i1.ID ,i2.ID FRIENDID
FROM
userdata d
INNER JOIN
userids i1 ON (i1.USER=d.FRIENDID)
INNER JOIN
userids i2 ON (i2.USER=d.ID)')
INFO AGE ID FRIENDID
1 foo 43 1 4
2 foo 53 3 1
3 bar 26 2 3
But this this removes NA lines! maybe someone can suggest me something on how to deal with NA!
EDIT
Thanks to G. Grothendieck comment, replacing the INNER by LEFT we get the result.
sqldf('SELECT d.INFO,d.AGE,i1.ID ,i2.ID FRIENDID
FROM
userdata d
LEFT JOIN
userids i1 ON (i1.USER=d.FRIENDID)
LEFT JOIN
userids i2 ON (i2.USER=d.ID)')
INFO AGE ID FRIENDID
1 foo 43 1 4
2 bar 33 NA 2
3 foo 53 3 1
4 bar 26 2 3
Use match
:
userdata$ID <- userids$ID[match(userdata$ID, userids$USER)]
userdata$FRIENDID <- userids$ID[match(userdata$FRIENDID, userids$USER)]
This is a possibility:
library(qdap)
userdata$FRIENDID <- lookup(userdata$FRIENDID, userids)
userdata$ID <- lookup(userdata$ID, userids)
or to win the one line prize:
userdata[, c(2, 4)] <- lapply(userdata[, c(2, 4)], lookup, key.match=userids)
Here's a possible solution, which will also work on datasets with multiple records of each ID, though we will need to coerce the ID and FRIENDID variables to character first:
> userdata$ID <- sapply(userdata$ID, function(x){gsub(x, userids[userids$USER==x, 2], x)})
> userdata$FRIENDID <- sapply(userdata$FRIENDID, function(x){gsub(x, userids[userids$USER==x, 2], x)})