Java: Array with loop

Question

I need to create an array with 100 numbers (1-100) and then calculate how much it all will be (1+2+3+4+..+100 = sum).

I don\'t want to enter these numbers into the a

Answer 1

If all you want to do is calculate the sum of 1,2,3... n then you could use :

 int sum = (n * (n + 1)) / 2;

Answer 2

If your array of numbers always is starting with 1 and ending with X then you could use the following formula: sum = x * (x+1) / 2

from 1 till 100 the sum would be 100 * 101 / 2 = 5050

Answer 3

The Array has declared without intializing the values and if you want to insert values by itterating the loop this code will work.

Public Class Program
{

public static void main(String args[])

{
 //Array Intialization
 int my[] = new int[6];

 for(int i=0;i<=5;i++)

{

//Storing array values in array
my[i]= i;

//Printing array values

System.out.println(my[i]);

}

}

}

Answer 4

Here's how:

// Create an array with room for 100 integers
int[] nums = new int[100];

// Fill it with numbers using a for-loop
for (int i = 0; i < nums.length; i++)
    nums[i] = i + 1;  // +1 since we want 1-100 and not 0-99

// Compute sum
int sum = 0;
for (int n : nums)
    sum += n;

// Print the result (5050)
System.out.println(sum);

Answer 5

To populate the array:

int[] numbers = new int[100];
for (int i = 0; i < 100; i++) {
    numbers[i] = i+1;
}

and then to sum it:

int ans = 0;
for (int i = 0; i < numbers.length; i++) {
    ans += numbers[i];
}

or in short, if you want the sum from 1 to n:

( n ( n +1) ) / 2

Answer 6

int count = 100;
int total = 0;
int[] numbers = new int[count];
for (int i=0; count>i; i++) {
    numbers[i] = i+1;
    total += i+1;
}
// done