Return FileName Only when using OpenFileDialog

Question

I am using the following method to browse for a file:

    OpenFileDialog.ShowDialog()
    PictureNameTextEdit.Text = OpenFileDialog.FileName

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Answer 1

C++ code for obtain filename and complete path in OpenFileDialog:

textBox1->Text = OpenFileDialog1->FileName; //complete path textBox1->Text = System::IO::Path::GetFileName(OpenFileDialog1->FileName); //filename

Answer 2

//Following code return file name only 

string[] FileFullPath;
string FileName;
objOpenFileDialog.Title = "Select Center Logo";
objOpenFileDialog.ShowDialog();

FileFullPath = objOpenFileDialog.FileNames[0].ToString().Split('\\');
FileName = FileFullPath[FileFullPath.Length - 1]; //return only File Name

//Use following code if u want save other folder , 
// following code save file to CenterLogo  folder which inside bin folder//

System.IO.File.Copy(OFD.FileName, Application.StartupPath + 
"/CenterLogo/" + FileName, true);